IQ scores are normally distributed with a mean of 100 and a standard deviation of 16.
1 answer:
Answer:
<u>Given</u>
a)
x = 68
- z = (x - μ)/σ =
- (68 - 100)/16 = -2
- z-score = 0.0228 = 2.28%
b)
x = 100 and x = 132
- z = (100 - 100)/16 = 0, z-score = 50%
- z = (132 - 100)/16 = 2, z-score = 0.9772 = 97.72%
- 97.72% - 50% = 47.72%
c)
68% confidence interval, <u><em>assumed sample number n = 100</em></u>
z-score representing 68% = 0.47
- CI = μ ± z× σ/√n
- CI = 100 ± 0.47*16/√100 =
- = 100 ± 0.752
d)
- n = 10000
- x = 148
- z = (148 - 100)/16 = 3, z-score is 0.9987
<u>Number of people scored above 148:</u>
- (1 - 0.9987)*10000 = 13 people
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