Which is an equation of a circle with center (2, -1) that passes through the point (3, 4)?

1 answer:

8 0

Equation of circle is (x - a)^2 + (y - b)^2 = r^2; where (a, b) is the center and r is the radius.
r^2 = (2 - 3)^2 + (-1 - 4)^2 = (-1)^2 + (-5)^2 = 1 + 25 = 26
Equation is (x - 2)^2 + (y + 1)^2 = 26

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Find the altitude of a cylinder with with a radius of 9 and a surface area of approximately 791.68 units2.

Vika [28.1K]

In this question , it is given that we have a cylinder with with a radius of 9 and a surface area of approximately 791.68 units square.

The formula of surface area of cylinder is

$A= 2 \pi r^2 + 2 \pi r h$

Substituting the values of A and r, we will get

$791.68 = 2* \pi * 9^2 + 2 * \pi * 9*h
\\
791.68 = 162 \pi + 18 \pi h
\\
791.68 -162 \pi = 18 \pi h
\\
h = \frac{791.68 -162 \pi}{18 \pi}
\\
h =5 units$