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pentagon [3]
3 years ago
8

Emmanuel bought 28 lb of potting soil this week. This amount is 4 lb more than twice the amount of potting soil he bought last w

eek. How many pounds of soil did Emmanuel purchase last week? If p represents the pounds of soil he bought last week, what does p stand for?
Mathematics
1 answer:
hammer [34]3 years ago
5 0
He bought 60 pounds last week and p stands for 60
You might be interested in
40.00 jeans 20% discount
Svetllana [295]
20(40)
\frac{20}{100} = 0.2
0.2(40) = 8

After price: $32.00
But, you save: $8

4 0
3 years ago
Alicia drove at a constant speed and traveled 183 in 3 hours
Viefleur [7K]

Answer:

671

Step-by-step explanation:

lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol   lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lollol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol ol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol   lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol lol

8 0
3 years ago
An automobile manufacturer has given its car a 46.7 miles/gallon (MPG) rating. An independent testing firm has been contracted t
erastova [34]

Answer:

z=\frac{46.5-46.7}{\frac{1.1}{\sqrt{150}}}=-2.23    

The p value would be given by:

p_v =2*P(z  

For this case since th p value is lower than the significance level of0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true mean for this case is significantly different from 46.7 MPG

Step-by-step explanation:

Information given

\bar X=46.5 represent the mean

\sigma=1.1 represent the population standard deviation

n=150 sample size  

\mu_o =46.7 represent the value to verify

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true mean for this case is 46.7, the system of hypothesis would be:  

Null hypothesis:\mu = 46.7  

Alternative hypothesis:\mu \neq 46.7  

Since we know the population deviation the statistic is given by:

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

Replacing we got:

z=\frac{46.5-46.7}{\frac{1.1}{\sqrt{150}}}=-2.23    

The p value would be given by:

p_v =2*P(z  

For this case since th p value is lower than the significance level of0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true mean for this case is significantly different from 46.7 MPG

7 0
3 years ago
JELP HELP HELP HELP<br> HELP HELP HELP<br> 5TH GRADE<br> HELP
sergey [27]

Answer: A 729

Step-by-step explanation:

5 0
2 years ago
HELP A FELLA OUT Please
Vanyuwa [196]

I'll write "x" instead theta.

sin x + 1 = cos(2x)

formula: cos(2x) = 1 - 2sin²x

sin x + 1 = 1 - 2sin²x

2sin²x + sin x = 0

sin x (2sin x + 1) = 0

sin x = 0 or sin x = -1/2

x1 = πk and x2 = -π/6 + 2πk and

x3 = 5π/6 + 2πk

for domain 0≤x<2π :

x1 = 0 (for k=0 in x1)

x2 = π (for k=1 in x1

x3 = 11π/6 (for k=1 in x2)

x4 = 5π/6 (for k=0 in x3).

k is an integral.

8 0
3 years ago
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