There are 36 possible combinations that can occur when 2 dice are rolled. For the sake of this question, we'll count instances where dice 1 = 3/dice 2 = 2 and dice 1 = 2/dice 2 = 3.
Now, let's think about all of the possible ways a total of 5 could be rolled.
1 + 4
2 + 3
3 + 2
4 + 1
That's 4 possibilities to roll a total of 5 out of 36 possible outcomes.
4 / 36 = ? / 180
---Now, we need to use a proportion in order to figure out the possibilities out of 180.
36x = 720
x = 20
If you rolled a pair of fair dice 180 times, you would expect to roll a total of 5, 20 times.
Hope this helps!
Answer:
61.712
Step-by-step explanation:
Multiply .8x.04
Multiply .8x.0
Multiply .8x2
Multiply .8x2
Than add a zero under the answer of .8x.04
Multiply 2x.04
Multiply 2x.0
Multiply 2x2
Multiply 2x 2
Answer:
157
Step-by-step explanation:
formula- 2 x 3.14 x 5 squared
6.28 x 5 squared
6.28 x 25
157
Answer:
if it is thren true (???) you gots to be more specific...pls)
Step-by-step explanation:
is this a trues or false satement
Answer:
3
Step-by-step explanation:
lim(t→∞) [t ln(1 + 3/t) ]
If we evaluate the limit, we get:
∞ ln(1 + 3/∞)
∞ ln(1 + 0)
∞ 0
This is undetermined. To apply L'Hopital's rule, we need to rewrite this so the limit evaluates to ∞/∞ or 0/0.
lim(t→∞) [t ln(1 + 3/t) ]
lim(t→∞) [ln(1 + 3/t) / (1/t)]
This evaluates to 0/0. We can simplify a little with u substitution:
lim(u→0) [ln(1 + 3u) / u]
Applying L'Hopital's rule:
lim(u→0) [1/(1 + 3u) × 3 / 1]
lim(u→0) [3 / (1 + 3u)]
3 / (1 + 0)
3
