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Hoochie [10]
2 years ago
8

I need help with the answer.

Mathematics
2 answers:
Gennadij [26K]2 years ago
6 0

The answer is A, 13

Step-by-step explanation:

The easy way to solve it was to plug in every answer to see which was equal to 32 since both sides were identical.

arlik [135]2 years ago
3 0
The answer would be a which is 13 so the person on top was correct
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Molly uses 192 beads to make a bracelet and a necklace. It takes 5 times as many beads to make a necklace than t does to make a
neonofarm [45]
Solve for the bracelet first. x represents number of beads for bracelet So it would be number of beads for the bracelet + number of beads for necklace (5x) and they both equal 192 x + 5x = 192 Then you would add the x and 5x.<br />6x = 192 Now all you have to do is divide by 6 on both sides. 6× ÷ 6 = 192 ÷ 6 You know have the number of beads it takes for a bracelet. x = 32 to get the necklace all you need to do is multiply it by 5 because you need 5 times more for the necklace. 32 × 5 total beads needed is 160. 160 x+5x=192 6×=192 6x÷6=192÷6 x=32 necklace needs 32x5 beads per necklace is 160
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3 years ago
Which data set represents the histogram?
madam [21]
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2 years ago
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Question 2b only! Evaluate using the definition of the definite integral(that means using the limit of a Riemann sum
lara [203]

Answer:

Hello,

Step-by-step explanation:

We divide the interval [a b] in n equal parts.

\Delta x=\dfrac{b-a}{n} \\\\x_i=a+\Delta x *i \ for\ i=1\ to\ n\\\\y_i=x_i^2=(a+\Delta x *i)^2=a^2+(\Delta x *i)^2+2*a*\Delta x *i\\\\\\Area\ of\ i^{th} \ rectangle=R(x_i)=\Delta x * y_i\\

\displaystyle \sum_{i=1}^{n} R(x_i)=\dfrac{b-a}{n}*\sum_{i=1}^{n}\  (a^2 +(\dfrac{b-a}{n})^2*i^2+2*a*\dfrac{b-a}{n}*i)\\

=(b-a)^2*a^2+(\dfrac{b-a}{n})^3*\dfrac{n(n+1)(2n+1)}{6} +2*a*(\dfrac{b-a}{n})^2*\dfrac{n (n+1)} {2} \\\\\displaystyle \int\limits^a_b {x^2} \, dx = \lim_{n \to \infty} \sum_{i=1}^{n} R(x_i)\\\\=(b-a)*a^2+\dfrac{(b-a)^3 }{3} +a(b-a)^2\\\\=a^2b-a^3+\dfrac{1}{3} (b^3-3ab^2+3a^2b-a^3)+a^3+ab^2-2a^2b\\\\=\dfrac{b^3}{3}-ab^2+ab^2+a^2b+a^2b-2a^2b-\dfrac{a^3}{3}  \\\\\\\boxed{\int\limits^a_b {x^2} \, dx =\dfrac{b^3}{3} -\dfrac{a^3}{3}}\\

4 0
2 years ago
Can someone help meeee
GarryVolchara [31]

Answer:

1. 0

2. undefined

3. -3/2

Step-by-step explanation:

y=-3/2. This value is constant and the x does not change the value at all. so the coordinate are going to be (x, -3/2) so if we take any 2 values you're going to get (-3/2 - (-3/2)) / (x2 - x1) = (-3/2 + 3/2) / (x2 - x1) = (0) / (x2 - x1) which is always going to be 0.

x=-3/2. This value is also constant except the x-value does not vary at all so x2 and x1 are always going to be equal which will result in a 0 as the denominator thus making the slope undefined

y=-3/2x. it's just -3/2 given the slope-intercept form y=mx+b where m is the slope

4 0
1 year ago
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pav-90 [236]
142/10= 14.2
Can’t get half a box
Answer:15 boxes
7 0
3 years ago
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