Answer with Step-by-step explanation:
We are given that if sum of several numbers is odd
We have to prove that at least one of the number is itself odd.
Suppose, we have three numbers
a=6 , b=7,d=8
Sum of numbers=6+7+8=21=Odd number
We know that sum of two odd numbers is always an even number.
Sum of an odd number and an even number is always an odd number.
If we take even odd numbers then sum is always an even number and sum of odd odd numbers then the sum is always an odd number.
Sum of even numbers is always an even number.
Hence, there are atleast one numebr is odd then the sum of several number is odd.
One approach that might be a great help would be if you would look
at the choices ... those things at the bottom of the question that you
didn't give us.
-- One leg is 3 times the length of the other leg.
-- Any right triangle that has one leg three times as long as the other
leg is similar to this triangle.
I'll bet that if you look through the choices, you'll find one there.
You solve for y
4y=-6x+2
y=-6/4x+2
y=-2/3x+2
Slope is -2/3, the number in front of x is the slope.
Answer:
The answer is 62.17
Step-by-step explanation:
Because 3 in the thousandths is not equal to or greater than 5
(1/2)^2 = 1/4
2-2/3 = 6/3 - 2/3 = 4/3
OK so:
(1/2)^2 - 6(2-2/3) = 1/4 - 6(4/3)
= 1/4 - 8
= 1/4 - 32/4
= -31/4
