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REY [17]
3 years ago
6

There are 120 horses on a farm. 1/2 of the horses are brown, 1/3 of the horses are black and 1/6 of the horses are spotted. How

many horses are there of each color
Mathematics
1 answer:
romanna [79]3 years ago
8 0

There are 60 brown horses and 40 black horses and 20 spotted horses

<em><u>Solution:</u></em>

Given that there are 120 horses on a farm

\frac{1}{2} of the horses are brown

<em><u>Number of brown horses are:</u></em>

Therefore, 1/2 of total number of horses are brown

\frac{1}{2} of 120

\text{ brown horses } = \frac{1}{2} \text{ of } 120\\\\\text{ brown horses } = \frac{1}{2} \times 120\\\\\text{ brown horses } = 60

\frac{1}{3} of the horses are black

<em><u>Number of black horses are:</u></em>

Therefore, 1/3 of total number of horses are black

\frac{1}{3} of 120

\text{ Black horses } = \frac{1}{3} \text{ of } 120\\\\\text{ Black horses } = \frac{1}{3} \times 120\\\\\text{ Black horses } = 40

\frac{1}{6} of the horses are spotted

<em><u>Number of spotted horses:</u></em>

Therefore, 1/6 of total number of horses are spotted

\frac{1}{6} of 120

\text{ Spotted horses } = \frac{1}{6} \times 120 = 20

Thus there are 60 brown horses and 40 black horses and 20 spotted horses

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Answers:

C, D, E

Step-by-step explanation:

A rational number is a integer. It is also a terminating or repeating decimal.

A rational number can be written as a fraction of two integers.

Answer A is not correct because it's decimal never ends. It is also not repeating. A cannot be written as a fraction.

Answer B is not correct because the square root is not a whole number, or a perfect square. The square root has a non-terminating and non-repeating decimal, just like A. B cannot be written as a fraction.

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Out of the options given, C, D, and E have rational numbers, while all others do not.

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3 0
3 years ago
The sum of two numbers is 84 the first is nine more than four times the second find the numbers
Genrish500 [490]

The numbers are 69 and 15

Step-by-step explanation:

The given is:

  • The sum of two numbers is 84
  • The first is nine more than four times the second

We need to find the two numbers

Assume that the 1st number is x and the 2nd number is y

∵ The sum of the two numbers are 84

∵ The 1st number is x and the 2nd number is y

- Add x and y, then equate the sum by 84

∴ x + y = 84 ⇒ (1)

∵ The first is nine more than four times the second

- Multiply y by 4 and add the product to 9, then equate

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∴ x = 4y + 9 ⇒ (2)

Now we have a system of equations to solve it

Substitute x in equation (1) by equation (2)

∵ (4y + 9) + y = 84

- Add the like terms in the left hand side

∵ (4y + y) + 9 = 84

∴ 5y + 9 = 84

- Subtract 9 from both sides

∴ 5y = 75

- Divide both sides by 5

∴ y = 15

- Substitute the value of y in equation (2) to find x

∵ x = 4(15) + 9

∴ x = 60 + 9

∴ x = 69

The numbers are 69 and 15

Learn more:

You can learn more about the system of equations in brainly.com/question/2115716

#LearnwithBrainly

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7q^2 - 28 = 0

7q^2 = 28 
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Answer:

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