There are 60 brown horses and 40 black horses and 20 spotted horses
<em><u>Solution:</u></em>
Given that there are 120 horses on a farm
of the horses are brown
<em><u>Number of brown horses are:</u></em>
Therefore, 1/2 of total number of horses are brown
of 120
![\text{ brown horses } = \frac{1}{2} \text{ of } 120\\\\\text{ brown horses } = \frac{1}{2} \times 120\\\\\text{ brown horses } = 60](https://tex.z-dn.net/?f=%5Ctext%7B%20brown%20horses%20%7D%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%5Ctext%7B%20of%20%7D%20120%5C%5C%5C%5C%5Ctext%7B%20brown%20horses%20%7D%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%20120%5C%5C%5C%5C%5Ctext%7B%20brown%20horses%20%7D%20%3D%2060)
of the horses are black
<em><u>Number of black horses are:</u></em>
Therefore, 1/3 of total number of horses are black
of 120
![\text{ Black horses } = \frac{1}{3} \text{ of } 120\\\\\text{ Black horses } = \frac{1}{3} \times 120\\\\\text{ Black horses } = 40](https://tex.z-dn.net/?f=%5Ctext%7B%20Black%20horses%20%7D%20%3D%20%5Cfrac%7B1%7D%7B3%7D%20%5Ctext%7B%20of%20%7D%20120%5C%5C%5C%5C%5Ctext%7B%20Black%20horses%20%7D%20%3D%20%5Cfrac%7B1%7D%7B3%7D%20%5Ctimes%20120%5C%5C%5C%5C%5Ctext%7B%20Black%20horses%20%7D%20%3D%2040)
of the horses are spotted
<em><u>Number of spotted horses:</u></em>
Therefore, 1/6 of total number of horses are spotted
of 120
![\text{ Spotted horses } = \frac{1}{6} \times 120 = 20](https://tex.z-dn.net/?f=%5Ctext%7B%20Spotted%20horses%20%7D%20%3D%20%5Cfrac%7B1%7D%7B6%7D%20%5Ctimes%20120%20%3D%2020)
Thus there are 60 brown horses and 40 black horses and 20 spotted horses