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Blababa [14]
3 years ago
10

The solution set for 7q2 − 28 = 0 is { }. (Separate the solutions with a comma) NextReset

Mathematics
2 answers:
SVETLANKA909090 [29]3 years ago
6 0
7q^2 - 28 = 0

7q^2 = 28 
q^2 = 4
q = +/-2
 solution set is {-2,2}
exis [7]3 years ago
4 0

Answer:

{ 2,-2}

Step-by-step explanation:

In order to solve this set we just have to first clear the "q":

7q^{2} -28=0\\7q^{2} -28+28=+28\\7q^{2} =28\\\frac{7q^{2}}{7}  =\frac{28}{7} \\q^{2}=4\\\sqrt{q^{2}} =\sqrt{4} \\q= 2, -2

So as we know the solution for a square root is always a negative and positive number, so the solutions ser for 7q2-28=0 is 2 and -2

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