Question

The solution set for 7q2 − 28 = 0 is { }. (Separate the solutions with a comma) NextReset

Answer 1

7q^2 - 28 = 0

7q^2 = 28 
q^2 = 4
q = +/-2
 solution set is {-2,2}

Answer 2

Answer:

{ 2,-2}

Step-by-step explanation:

In order to solve this set we just have to first clear the "q":

$7q^{2} -28=0\\7q^{2} -28+28=+28\\7q^{2} =28\\\frac{7q^{2}}{7} =\frac{28}{7} \\q^{2}=4\\\sqrt{q^{2}} =\sqrt{4} \\q= 2, -2$

So as we know the solution for a square root is always a negative and positive number, so the solutions ser for 7q2-28=0 is 2 and -2