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oksano4ka [1.4K]
3 years ago
15

Pls help (kinda easy)

Mathematics
2 answers:
iren [92.7K]3 years ago
7 0

Answer:

b

Step-by-step explanation:

3241004551 [841]3 years ago
5 0

Answer:

f(x)=(2x+1)(2x-1).

Step-by-step explanation:

We want to convert the function into the form that let's us easily find the x-intercept, and it would be for the form (ax+b)(cx+d) because then we can find the x-intercept in the following manner:

(ax+b)(cx+d)=0

x=-b/a

x=-d/c

We factor our function f(x)=4x^2-1 and get

\boxed{f(x)=(2x+1)(2x-1)}

Now this form let's us easily find the x-intercepts:

x=-1/2

x=1/2

and so we pick the second choice: f(x)=(2x+1)(2x-1).

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ivanzaharov [21]

\log_b \left(\dfrac 1{b^{-b}}\right)\\\\=\log_b (b^{-b})^{-1}\\\\=\log_b  b^b\\\\=b \log_b b\\\\=b \cdot 1\\\\=b

3 0
2 years ago
There were 407 boys and 438 girls who like to join the Independence Day parade. How many buses will be hired if 65 persons can b
AURORKA [14]

Answer:

13

Step-by-step explanation:

just add them both and divide by 65

4 0
3 years ago
Read 2 more answers
If n is a term of the sequence 14, 8, 2, -4, …, which expression would you give the value of n?
Ipatiy [6.2K]

Answer:

-6n+20

Step-by-step explanation:

The given  term of sequece is  14, 8, 2, -4, …,

Here the first term is 14 and then the terms are decreasing by 6 each time  because 14-8=8-2=...=6

As we know that the nth term of the sequence is given by the formula

t_n=a+(n-1)d\\\text{Substitute the values we get}\\t_n=14+(n-1)(-6)\\t_n=14-6n+6\\t_n=20-6n\\

If n is a term of the given sequence sequence, then its value is -6n+20

7 0
3 years ago
Let f(x) = cxe−x2 if x ≥ 0 and f(x) = 0 if x &lt; 0.
sergij07 [2.7K]

(a) If <em>f(x)</em> is to be a proper density function, then its integral over the given support must evaulate to 1:

\displaystyle\int_{-\infty}^\infty f(x)\,\mathrm dx = \int_0^\infty cxe^{-x^2}\,\mathrm dx=1

For the integral, substitute <em>u</em> = <em>x</em> ² and d<em>u</em> = 2<em>x</em> d<em>x</em>. Then as <em>x</em> → 0, <em>u</em> → 0; as <em>x</em> → ∞, <em>u</em> → ∞:

\displaystyle\frac12\int_0^\infty ce^{-u}\,\mathrm du=\frac c2\left(\lim_{u\to\infty}(-e^{-u})-(-1)\right)=1

which reduces to

<em>c</em> / 2 (0 + 1) = 1   →   <em>c</em> = 2

(b) Find the probability P(1 < <em>X </em>< 3) by integrating the density function over [1, 3] (I'll omit the steps because it's the same process as in (a)):

\displaystyle\int_1^3 2xe^{-x^2}\,\mathrm dx = \boxed{\frac{e^8-1}{e^9}} \approx 0.3678

5 0
3 years ago
Equivalent to 10 minus 8
Reptile [31]
1+1


Hope this helps!
5 0
4 years ago
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