Solution :
Given that :
The radius of circle A = 6 cm
The radius of circle C = 4 cm
In circle A
The length of arc EF = 
= 14.653 cm
In circle C
The length of arc GH =
= 9.769 cm
Therefore,
The length of EF is 14.653 cm
The length of GH is 9.769 cm
The length of EF is 1.5 times the length of GH
i.e. 14.653 = 1.5 x 9.769
14.653 = 14.653
Hence proved.
Answer:
∆STR ~ ∆RTQ
Step-by-step explanation:
For two fugures to be considered similar, it means the corresponding sides are proportional, and as such, the ratio of their corresponding sides are equal.
However, the corresponding angles of two similar figures are the same and equal.
Taking a look at the figure of the triangle given, ∆STR is a right angle triangle, and it is similar to ∆RTQ as the angle formed at <T in ∆RTQ = 90°.
<T in ∆STR = <T in ∆RTQ.
Therefore, the correct similarity statement is ∆STR ~ ∆RTQ.
The last option is correct.
C is the answer ... all u has to do was subtract 5 from 12 , then -11-14 , then -13-9
Answer:
n*8=24
Step-by-step explanation:
3*8=24
