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garri49 [273]
3 years ago
8

Urn 1 contains 7 red balls and 4 black balls. Urn 2 contains 3 red ball and 1 black ball. Urn 3 contains 5 red balls and 1 black

balls. If an urn is selected at random and a ball is drawn, find the probability that it be red.
Mathematics
1 answer:
Marrrta [24]3 years ago
5 0
Choice urn_1: 1/3
    choice R: 5/8        ==>1/3*5/8=5/24
Choice urn_2: 1/3
   Choice R: 3/4        ==> 1/3*3/4=1/4
Choice urn_3: 1/3
   Choice R:4/6=2/3  ==> 1/3*2/3=2/9

Total: 5/24+1/4+2/9=15/72+18/72+16/72=49/72

Read more on Brainly.com - brainly.com/question/1904508#readmore
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Express each ratio as a fraction in simplest form. A. 2/29 B. 29/10 C. 20/29 D. 10/29
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6 0
3 years ago
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Fill in the rest of the table.
Vinvika [58]

9514 1404 393

Answer:

top-down

  f(g(x)) = 1, 4, 5, 3, 2

  g(f(x)) = 5, 2, 4, 1, 3

Step-by-step explanation:

To find f(g(x)), locate g(x) in the third column (labeled g(x)). Use that value as x in the first column, then read f(x) from the second column.

Example: f(g(1)) = f(2) = 1

__

To find g(f(x)), locate f(x) in the second column (labeled f(x)). Use that value as x in the first column, and read the corresponding g(x) from the third column.

Example: g(f(1)) = g(2) = 5

6 0
3 years ago
I don’t know what to do, please help!!
Rainbow [258]

Answer:

b 7

Step-by-step explanation:

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then answer will be 7 to the power 1 which is equals to 7

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Step-by-step explanation:

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2 years ago
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e-lub [12.9K]

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