Urn 1 contains 7 red balls and 4 black balls. Urn 2 contains 3 red ball and 1 black ball. Urn 3 contains 5 red balls and 1 black

Question

garri49 [273]

3 years ago

8

Urn 1 contains 7 red balls and 4 black balls. Urn 2 contains 3 red ball and 1 black ball. Urn 3 contains 5 red balls and 1 black

balls. If an urn is selected at random and a ball is drawn, find the probability that it be red.

Mathematics

1 answer:

Marrrta [24] · Answer 1 · 2021-12-20T04:30:46+03:00

Choice urn_1: 1/3
choice R: 5/8 ==>1/3*5/8=5/24
Choice urn_2: 1/3
Choice R: 3/4 ==> 1/3*3/4=1/4
Choice urn_3: 1/3
Choice R:4/6=2/3 ==> 1/3*2/3=2/9

Total: 5/24+1/4+2/9=15/72+18/72+16/72=49/72

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