The two factors of a quadratic equation can be multiplied to form the original equation. Let the missing term be a:
y² + 15y + 56 = (y + 7)(y + a)
y² + 15y + 56 = y² + (7 + a)y + 7a
We can now compare the coefficient of the like terms, either the one with y or the one without y, and find the value of a.
15 = 7 + a; a = 8
OR
56 = 7a; a = 8
Second factor is (y + 8)
Answer:
Step-by-step explanation:
1. JK ∥ LM, KL ∥ MN Given
2. ∠KJL ≅ ∠MLN; ∠KLJ ≅ ∠MNL c. Corresponding Angles
3. JK ≅ LM Given
4. ∆JKL ≅ ∆LMN e. AAS
it would be 3 because when you add it, it gets to be 932 and the tens place is 3.
Answer:
an = -6n + 5.
Step-by-step explanation:
This is an arithmetic sequence with first term a1 = -1 and common difference d = -6
an = a1 + d(n-1)
an = -1 + -6(n - 1)
an = -1 -6n + 6
an = -6n + 5.
The average speed of the runner is 12.7 mph and 20.4 km/h
Given that the runner ran 26.2 mile in 2hr and 4 minutes, we start of by converting the time from hours and minutes into minutes and finally hours, since hours is what we need. So, we have
2hr = 120mins
+ 4 mins = 124 mins
124 mins ÷ 60 hour/mins = 2.06 hours.
This means that the runner finished the race in 2.06 hours.
If we are to find the average speed in mile per hour, we have
Average speed = distance ran ÷ time taken
Average speed = 26.2 ÷ 2.06
Average speed = 12.7 mph
From the speed in mph, we can directly convert it to km/hr by saying
1 mph = 1.609 km/h
12.7 mph = 12.7 * 1.609 = 20.4 km/hr
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