Answer:
In order for it to benefit his father to buy the pass Seth have to attend the movies for 11 times.
Step-by-step explanation:
Given:
Cost of movie pass = $40
Cost per matinees with pass = $1.00
Cost per matinees without pass = $3.50
To Find:
Number of times must Seth attend in order for it to benefit his father to buy the pass = ?
Solution:
Let x be the number of times he wants to visit
To profit his father
The number of visits without pass = the number of visits with passin the cost of $3.50
Then, without pass if he visits for x times then the cost will be = 3.50x
Also with pass, the number of times he can visit the pass = 
then
x = 11.42
x = 11 (approx)
Answer: I do not have expertise on this so I won't answer the exact problem but this sounds like exponential decay, where you have the decay rate. I know that the formula for exponential decay is: y = a(1 - r)^x
I'm sorry if this does not help much I don't have expertise on this. Sorry again.
Step-by-step explanation:
Answer:
Step-by-step explanation:
<u>Step 1: Divide both sides by 6</u>
<u>Step 2: Square root both sides</u>
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Answer:
Answer:
D
Step-by-step explanation:
In the other tables, their y values have a constant rate of change while as D does not.
Rate of Change for:
A = 5
B = 0.75
C = -5
D = Not Constant (+2 -> +3 -> +4)
Answer:
solution: x= 0.273, y= 1.909.
Step-by-step explanation:
- given system of linear equations : x+3y=64x−6y=6
- these can also be splitted or written individually as:
x+3y=6 & 64x−6y=6
- the first equation can also be written as,
so, it is line with slope : -1/3 and y-intercept :2
- the second equation can also be written as,
so, it is line with slope : 32/3 and y-intercept : -1
- now we can easily draw graphs for these equations using the above interpretation.
- graph is in the attachment.
- so, the solution is: x= 0.273, y= 1.909.
