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qwelly [4]
2 years ago
14

The grade point averages of a large population of college students are approximately normally distributed with a mean of 2.4 and

a standard deviation of 0.8.What is the probability that a randomly selected student will have a grade point average in excess of 3.0?
Round your answer to 4 decimal places.
Mathematics
1 answer:
ivanzaharov [21]2 years ago
4 0

Answer:

0.2266

Step-by-step explanation:

We know that the grade point averages of a large population of college students are approximately normally distributed with a mean of 2.4 and a standard deviation of 0.8. The z-score related to 3.0 is computed as (3.0-2.4)/0.8 = 0.75. Therefore the probability that a randomly selected student will have a grade point average in excess of 3.0 is P(Z > 0.75) where Z comes from a standard normal distribution. So, P(Z > 0.75) = 0.2266

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A line is parallel to y=4x-2 and intersects the point (-1, -2) what is the equation of this parallel line?
Tema [17]

Answer:

y = 4x + 2

Step-by-step explanation:

Please let me know if you want me to add an explanation as to why this is the answer. I can definitely do that, I just wouldn’t want to write it if you don’t want me to :)

8 0
2 years ago
Without a calculator how would you solve this?
mina [271]

Answer:

the largest number that is less than (2+√3)^6 is 2701

Step-by-step explanation:

\bigstar \ (2+\sqrt{3})^6= \\\\C{}^{0}_{6}2^{6}+C{}^{1}_{6}2^{5}\sqrt{3}^1+C{}^{2}_{6}2^{4}\sqrt{3}^2+C{}^{3}_{6}2^{3}\sqrt{3}^3+C{}^{4}_{6}2^{2}\sqrt{3}^4+C{}^{5}_{6}2^{1}\sqrt{3}^5+C{}^{6}_{6}\sqrt{3}^6

=64+192\sqrt{3}+720 +480\sqrt{3} +540+108\sqrt{3} +27\\=1351+780\sqrt{3}

\bigstar\  (2-\sqrt{3} )^6 =\\\\1351-780\sqrt{3}

\bigstar\  \bigstar\  (2+\sqrt{3} )^6+(2-\sqrt{3} )^6 =\\\\1351+780\sqrt{3}+1351-780\sqrt{3}

\Longrightarrow(2+\sqrt{3} )^6+(2-\sqrt{3} )^6 =2702

\Longrightarrow(2+\sqrt{3} )^6 =2702-(2-\sqrt{3} )^6

0 < \left( 2-\sqrt{3} \right) < 1 \Longrightarrow 0 < \left( 2-\sqrt{3} \right)^{6} < 1 \Longrightarrow-1 < \left( 2-\sqrt{3} \right)^{6} < 0

\Longrightarrow2702-1 < 2702-\left( 2-\sqrt{3} \right)^{6} < 2702+0

\Longrightarrow 2701 < \left( 2+\sqrt{3} \right)^{6} < 2702

8 0
2 years ago
Find the domain of <br> f(x)= (x+3)(x-5)/(x-5)(x+4)
EastWind [94]
The domain would be (x+3) (x+4) you basically just cancel out both of the (x-5)
7 0
3 years ago
HELP ME WITH THIS WHO ANSWERS CORRECTLY I WILL GIVE BRAINLIEST!
motikmotik

Answer:conjectured that F(n)≈0.72∗n∗f(n). Following that clue, we can find the following identity holds for all cases we tested by trial and error.

F(n)=nf(n)−(n−2)f(n−2)+(n−4)f(n−4)−(n−6)f(n−6)+⋯

where the sequence of summands goes on as long as the summand makes sense.

Step-by-step explanation:

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3 years ago
Please help!!
zalisa [80]
The answer to your question is 0.667
4 0
2 years ago
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