<em> $answer = 32.8 \\ solution \\ \frac{39}{y} + 5y \\ = \frac{39}{5} + 5 \times 5 \\ = \frac{39}{5} + 25 \\ = \frac{39 + 25 \times 5}{5} \\ = \frac{39 + 125}{5} \\ = \frac{164}{5} \\ = 32.8 \\ hope \: it \: helps$ </em>

3 0

3 years ago

Read 2 more answers

1=x+15 so I’m stuck on this

AlekseyPX

Answer:

-14

Step-by-step explanation:

4 0

3 years ago

13Given that log (xy) 3 and log, (x2y3)4Calculate the values of log, x and log, y

Nonamiya [84]

$If \ log_q(xy)=3, \ then \ log_qx+log_qy=3 \ . . . . . \ (1) \\ If \ log_q(x^2y^3)=4, \ then \ log_qx^2+log_qy^3=2log_qx+3log_qy=4 \ . . . . . \ (2) \\ From \ (1), \ log_qx=3-log_qy \\ substituting \ for \ log_qx \ in \ (2) \ gives: \\ 2(3-log_qy)+3log_qy=4 \\ 6-2log_qy+3log_qy=4 \\ \\ Therefore, \ log_qy=4-6=-2; \ and \\ log_qx=3-log_qy=3-(-2)=3+2=5$

8 0

3 years ago