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rusak2 [61]
3 years ago
10

PLEASE HELP ME ON THIS

Mathematics
2 answers:
Alex73 [517]3 years ago
6 0
It's B the second one
Svetlanka [38]3 years ago
4 0
The answer is 
8x+12y<96
x+y>10
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Use the following information to complete parts I, II and III.
Ber [7]

Answer:

see below

Step-by-step explanation:

Part I: Use scientific notation to estimate the number of hours in one year

Using the conversion factors

Estimate using scientific notation

31,556,952 seconds = 3.2 *  10^7

3600 seconds = 3.6 * 10 ^2

1 year = 3.2 *  10^7 seconds * 1 hour/ 3.6 * 10 ^2 seconds

3.2 /3.6 =.88888 (repeating)    

10^7 / 10^2 = 10^5

8.88888 * 10 ^5

8.888 * 10 ^4 hours

Part II: Use scientific notation to calculate the exact number of hours in one year.

 31,556,952 seconds = 3.1556952 *  10^7

3600 seconds = 3.6 * 10 ^2

1 year = 3.1556952 *  10^7 seconds * 1 hour/ 3.6 * 10 ^2 seconds

3.1556952 /3.6 =.876582    

10^7 / 10^2 = 10^5

.876582 * 10 ^5      

8.76582*10^4 hours

Part III: In two or more complete sentences, compare your answers to parts I and II. In your comparison, discuss similarities and differences in your answers.

Part II is an exact answer, where Part I is an estimate.  Both Parts give values in the thousands of hours,  and are both  between 8700 and 8900 hours.  Part I can be done without a calculator where Part II is much harder to do without a calculator.

7 0
3 years ago
Can anyone help me out??
Troyanec [42]

9514 1404 393

Answer:

  p(1) = 6

Step-by-step explanation:

The basic idea is to put 1 wherever you see x. That gives you ...

  p(1) = 2·1² +3·1 +1

The powers of x are all 1 when x=1, so the value of p(1) is just the sum of the coefficients:

  p(1) = 2 + 3 + 1

  p(1) = 6

7 0
3 years ago
Solve for x.
oee [108]
-ax+3b \ \textgreater \  5\ \ \ |subtract\ 3b\ from\ both\ sides\\\\-ax \ \textgreater \  5-3b\ \ \ \ |change\ signs\\\\ax \ \textless \  3b-5\ \ \ \ |divide\ both\ sides\ by\ a \ \textgreater \  0\\\\\boxed{x \ \textless \  \dfrac{3b-5}{a}}\\\\-ax \ \textgreater \  5-3b\ \ \ \ |divide\ both\ sides\ by\ (-a)\\\\\boxed{x \ \textless \  \dfrac{5-3b}{-a}\to x \ \textless \  \dfrac{-3b+5}{-a} }
7 0
4 years ago
Which relationship in the triangle must be true?
forsale [732]

Answer:

sinB=cos(90-B)

Step-by-step explanation:

this is the relationship between sin and cos. other choices are wrong

3 0
3 years ago
The distribution of the amount of money spent by first-time gamblers at a major casino in las vegas is approximately normal in s
Lostsunrise [7]

Solution: We are given:

\mu=600, \sigma =120

We need to find the z value corresponding to probability 0.84, in order to find the how much money almost 84% of gamblers spent at casino.

Using the standard normal table, we have:

z(0.85) = 0.9945

Now we will use the z score formula to find the required amount:

z=\frac{x-\mu}{\sigma}

0.9945=\frac{x-600}{120}

0.9945 \times 120 = x - 600

119.34 = x - 600

x = 600 + 119.34        

x = 719.34

x = 720 approximately

Therefore, almost 84% of gamblers spent more than $720 amount of money at this casino.

5 0
3 years ago
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