D + q = 40
.10d +.25q= $7.75
d +q = 40
d =40-q
.10(40-q) +.25q= $7.75
4 - .10q + .25q =7.75
4 +.15q =7.75
4-4 +.15q =7.75-4
.15q= 3.75
.15q/.15 = 3.75/.15
q = 25
d =40-25
d = 15
Check
.10(15) +.25(25)= $7.75
1.5+6.25=7.75
7.75=7.75
Answer:
Step-by-step explanation:
9514 1404 393
Answer:
see below
Step-by-step explanation:
Perhaps you're stuck because it is too simple. If any value in the x-column is repeated, the relation is <em>not</em> a function.
Of the two relations shown, the first is <em>not</em> a function (x=3 is repeated), and the second one is a function (all the x-values are different).
X+2y≤6 with x≥0 and y≥0
2x+y≤6
1st) Find the 1st shaded region: 1st Quadrant since x≥0 and y≥0
2nd) Let's find the x and y intercepts of 2x+y = 6
x-intercepts for y = 0 , x=6 →A(3,0)
y-intercepts for x = 0 , y =3→B(0,6) . Now Join AB
2nd shaded region
3rd) Let's find the x and y intercepts of x+2y = 6
x-intercepts for y = 0 , x=6 →C(6,0)
y-intercepts for x = 0 , y =3→D(0,3) . Now Join CD
3rd shaded region
4th) Now let's calculate the coordinate of the intersection point of
x+2y=6 and
2x+y =6 Solving it will give you x = 2 and y = 2 (coordinates of the intersection of AB with DC, le be E. (4th shaded region).
Re write all pairs:
A(3,6), B(0,6), C(6,0), D(0,3), E(2,2). Now plug in each pairs with the equation:
F= 5x + 2y
For A(3,6), →→F=15+12 = 25
For B(0,6), →→F=0+12 = 12
For C(6,0), →→F=30+0 = 30
For D(0,3), →→F=0+6 = 6
For E(2,2), →→F=20+4 = 14
So the max value of F= 5x+2y is 30 at C(6,0)
Hope that I didn't make any mistake
