Question

If f(x)= 2x^5-3x^3+2x^2+1, then f(1)=? A. -1 B. 0 C. 1 D. 2 E. 4

Answer 1

Answer:

2

Step-by-step explanation:

f(x)= 2x^5-3x^3+2x^2+1

Let x=1

f(1)= 2(1)^5-3(1)^3+2(1)^2+1

    = 2*1 -3*1+2(1) +1

     = 2-3+2+1

     2

Answer 2

Problem:

$\tt{if \: \: f(x) = 2 {x}^{5} - 3{x}^{3} + 2 {x}^{2} + 1 \: \: then \: \: f(1) = ?}$

Let's try!

$\quad \quad \quad \quad \tt{f(x) = 2 {x}^{5} - 3 {x}^{3} + 2 {x}^{2} + 1}$

$\quad \quad \quad \quad \tt{f(x) = 2 {(1)}^{5} - 3 {(1)}^{3} + 2 {(1)}^{2} + 1}$

$\quad \quad \quad \quad \tt{f(x) = 2 (1) - 3 (1) + 2 (1) + 1}$

$\quad \quad \quad \quad \tt{f(x) = 2 - 3 + 2 + 1}$

$\quad \quad \quad \quad \tt{f(x) = 2 - 3 +3}$

$\quad \quad \quad \quad \tt{f(x) = 2 \: \: \cancel{ \color{red}- 3 +3}}$

$\quad \quad \quad \quad \tt{f(x) = 2 }$

Hence, The answer is:

$\quad \quad \quad \quad \huge\boxed{\tt{ \color{green}f(x) = 2 }}$

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