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klasskru [66]
3 years ago
14

If f(x)= 2x^5-3x^3+2x^2+1, then f(1)=? A. -1 B. 0 C. 1 D. 2 E. 4

Mathematics
2 answers:
Ivahew [28]3 years ago
8 0

Answer:

2

Step-by-step explanation:

f(x)= 2x^5-3x^3+2x^2+1

Let x=1

f(1)= 2(1)^5-3(1)^3+2(1)^2+1

    = 2*1 -3*1+2(1) +1

     = 2-3+2+1

     2

Gemiola [76]3 years ago
7 0
<h2>Problem:</h2>

\tt{if  \: \: f(x) = 2 {x}^{5}  - 3{x}^{3}  + 2 {x}^{2}  + 1 \: \:  then  \: \: f(1) = ?}

<h2>Let's try!</h2>

\quad \quad \quad \quad \tt{f(x) = 2 {x}^{5}  - 3 {x}^{3}  + 2 {x}^{2}   + 1}

\quad \quad \quad \quad \tt{f(x) = 2 {(1)}^{5}  - 3 {(1)}^{3}  + 2 {(1)}^{2}   + 1}

\quad \quad \quad \quad \tt{f(x) = 2 (1)  - 3 (1)  + 2 (1)   + 1}

\quad \quad \quad \quad \tt{f(x) = 2  - 3  + 2    + 1}

\quad \quad \quad \quad \tt{f(x) = 2  - 3  +3}

\quad \quad \quad \quad \tt{f(x) = 2 \:  \:  \cancel{ \color{red}- 3  +3}}

\quad \quad \quad \quad \tt{f(x) = 2 }

<h3>Hence, The answer is:</h3><h3 /><h3>\quad \quad \quad \quad   \huge\boxed{\tt{ \color{green}f(x) = 2 }}</h3>

________

#LetsStudy

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