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Murrr4er [49]
3 years ago
12

3 Parts with a picture. Thanks!

Mathematics
1 answer:
tatuchka [14]3 years ago
7 0

We have $8.50 an hour gross minus $2.15 an hour tax and bennys.  Then $3.75 daily expense.  In one week our net take-away y after x hours is

y = x(8.50 - 2.15) - 5(3.75)

That's the answer, or we can simplify it to

Answer: y = 6.35 x - 18.75

Answer: The slope, 6.35, is the net dollars per hour <em>before weekly expenses.</em>

Answer: The y intercept, -18.75, is the weekly expense, negative because it's an expense.

To make $120 in a week, we solve for x where y=120

120 = 6.35x - 18.75

138.75 = 6.35 x

x = 138.75 / 6.35 = 21.8503937007874

That wasn't the nice round number I was expecting/hoping for.  I don't see a mistake so let's go with

Answer: 21.85 hours to make $120

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12 ft. 7 ft. what is the Hypotenuse<br>​
melisa1 [442]

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13.89

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About 30% of the population cannot detect any odor when they sniff the steroid androstenone, but they can become sensitive to it
iris [78.8K]

Using the z-distribution, as we are working with a proportion, it is found that there is enough evidence to conclude that the proportion is different of 50%.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if the proportion is of 0.5, that is:

H_0: p = 0.5


At the alternative hypothesis, it is tested if the proportion is different of 0.5, that is:

H_1: p \neq 0.5.

<h3>What is the test statistic?</h3>

The test statistic is given by:

z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}

In which:

  • \overline{p} is the sample proportion.
  • p is the proportion tested at the null hypothesis.
  • n is the sample size.

In this problem, the parameters are:

p = 0.5, n = 12, \overline{p} = \frac{10}{12} = 0.8333

Then, the value of the test statistic is as follows:

z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}

z = \frac{0.8333 - 0.5}{\sqrt{\frac{0.5(0.5)}{12}}}

z = 2.31

<h3>What is the decision?</h3>

Considering a <em>two-tailed test</em>, as we are testing if the proportion is different of a value, with a <em>significance level of 0.05</em>, the critical value is of |z^{\ast} = 1.96.

Since the absolute value of the test statistic is greater than the critical value for the two-tailed test, it is found that there is enough evidence to conclude that the proportion of participants that had improved androstenone-detection accuracy is different of 50%.

More can be learned about the z-distribution at brainly.com/question/26454209

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2 years ago
- 12 + 2y - y = 105.2319
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