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vazorg [7]
2 years ago
6

5z^3-2z^4-9z^2+z5z What is the degree of the polynomial?

Mathematics
1 answer:
WINSTONCH [101]2 years ago
5 0

Answer:

z6−2z4+5z3−9z2

Step-by-step explanation:

5z3−2z4−9z2+z5z

=5z3+−2z4+−9z2+z6

=z6-2z4+5z3-9z2

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HELPPPP!!!PLEASE!!!!!
lbvjy [14]

Answer:

x=40

Step-by-step explanation:

Both angles are equal. So the equation needs to equal 156.

Just plug in points for x until the answer is 156.

In this case, when we plug in 40, it works!

(3*40)+36=156

3 0
2 years ago
Read 2 more answers
Tilda is growing herbs from seeds. The heights of the herbs after one week are shown. Which plant is the tallest at the end of t
lukranit [14]

Answer:

Oregano

Step-by-step explanation:

Basil = 3.4

Parsley = 3.5

Dill = 3.15

oregano = 3.6666666

7 0
2 years ago
Read 2 more answers
A family of 12 went to the local Italian restaurant for dinner. Every family member ordered a drink and meal,3 ordered an appeti
egoroff_w [7]

Answer:

cost = 12 d + 12m + 3a + 6c

7 0
2 years ago
Quadratic 6X2 + 5X = -7
poizon [28]
Ok, so here your being asked to solve 6x2<span> + 5x = -7 

The procedure that I did was using this formula it led me to get the following:
</span>Using the formula:

x = -(-5) ± √(-5)² - 4(6)(-6)/ 2(6)
x = 5 ± √ 25 + 144 / 12
x = 5 ± √ 169 / 12
x = 5 ± 13/12

x1 = 5 + 13/12
x1 = 18/12
x1 = 3/2

x2 = 5 - 13/12
x2 = -8/12
<span> x2 = - 2/3 

Hope this helped :)</span>
7 0
3 years ago
Twelve percent of U.S. residents are in their forties. Consider a group of nine U.S. residents selected at random. Find the prob
miskamm [114]

Answer:

The probability is 28 % ( approx )

Step-by-step explanation:

Since, there are only two possible outcomes in every trails ( residents are in their forties or not ),

So, this is a binomial distribution,

Binomial distribution formula,

Probability of success in x trials,

P(x)=^nC_x p^x q^{n-x}

Where, ^nC_x=\frac{n!}{x!(n-x)!}

p and q are probability of success and failure respectively and n is the total number of trials.

Let X be the event of resident who are in his or her forties.

Here, p = 12% = 0.12,

⇒ q = 1 - p = 1 - 0.12 = 0.88,

n = 9,

Hence, the probability that two or three of the people in the group are in their forties = P(X=2) + P(X=3)

^9C_2 (0.12)^2 (0.88)^{9-2}+^9C_3 (0.12)^3 (0.88)^{9-3}

=36(0.12)^2 (0.88)^7+84(0.12)^3 (0.88)^6

=0.279266611163

\approx 0.28

=28\%

7 0
3 years ago
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