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Svetach [21]
3 years ago
13

Daisy needs 3/4 of a scoop of cream for one serving of a recipe. How many scoops of cream will she need for 5 serving?

Mathematics
2 answers:
Mrac [35]3 years ago
7 0

Answer:

Step-by-step explanation:

ongoing 6 i hope

Zina [86]3 years ago
4 0

Answer:

15/4 aka 3 3/4

Step-by-step explanation:

Multiply the top number by number of servings then simplify

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Find the possible value or values of y in the quadratic equation z^2 - 4z+ 4 =0
jeyben [28]
Didn't you mean "Find the possible value or values of z?  y is not at all present in this equation.

z^2 - 4z + 4 = 0 can be factored into (z-2)(z-2).  Thus, the given equation has two equal, real solutions:  z=2 and z=-2.
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Find the indicated length
Setler79 [48]

Answer:

x=6

AC = 28

Step-by-step explanation:

4x+4= AC

4x +4 = 14 + 3x -4

4x-3x= 14-4-4

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Graph the following lines and write the equation in slope-intercept form.
Taya2010 [7]

Answer:

y=mx+b

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1=y coordinate

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b=y intercept

Substitute m for 3

y=3x+b

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Solve

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+24 +24

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Step-by-step explanation:

3 0
3 years ago
Find the mean of 100​
goldfiish [28.3K]

Answer:

100.

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100 + 0 = 100

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8 0
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The length of each side of an equilateral triangle is increased by 20%, resulting in triangle ABC. If the length of each side of
kompoz [17]

Answer: Area of ΔABC is 2.25x the area of ΔDEF.

Step-by-step explanation: Because equilateral triangle has 3 equal sides, area is calculated as

A=\frac{\sqrt{3} }{4} a^{2}

with a as side of the triangle.

Triangle ABC is 20% bigger than the original, which means its side (a₁) measures, compared to the original:

a₁ = 1.2a

Then, its area is

A_{1}=\frac{\sqrt{3} }{4}(1.2a)^{2}

A_{1}=\frac{\sqrt{3} }{4}1.44a^{2}

Triangle DEF is 20% smaller than the original, which means its side is:

a₂ = 0.8a

So, area is

A_{2}=\frac{\sqrt{3} }{4} (0.8a)^{2}

A_{2}=\frac{\sqrt{3} }{4} 0.64a^{2}

Now, comparing areas:

\frac{A_{1}}{A_{2}}= (\frac{\sqrt{3}.1.44a^{2} }{4})(\frac{4}{\sqrt{3}.0.64a^{2} } )

\frac{A_{1}}{A_{2}} = 2.25

<u>The area of ΔABC is </u><u>2.25x</u><u> greater than the area of ΔDEF.</u>

7 0
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