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iren [92.7K]
3 years ago
13

Please help answer these question​ I will give you brainliest

Mathematics
2 answers:
ozzi3 years ago
8 0

Answer:

1) \frac{6+\sqrt{6} }{2}       2) -3 + \sqrt{12}

Step-by-step explanation:

Please ignore the squiggle in the middle of the page.

Please mark brainliest when you’re able :)  

Effectus [21]3 years ago
6 0

Answer:

1) ( 6+\sqrt{6} ) / 2                 2) 2 \sqrt{3} - 3

Step-by-step explanation:

I got the same thing as the other person, but typing it out would take forever just to give you the same result.

You do use a technique called rationalizing a denominator to eliminate the radical. The point of rationalizing a denominator is to make it easier to understand what the quantity really is by removing radicals from the denominators.

1) ( 6+\sqrt{6} ) / 2

2) I got the same answer but I put in 1 more step. It looks like the person caught it though.

From the -3 + \sqrt{12}    

-3 + \sqrt{4} \sqrt{3}

-3 + 2 \sqrt{3}     Rearrange

2 \sqrt{3} - 3

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It costs $25 for every 2-hour art class, how much would it cost for 6 hours of art classes
e-lub [12.9K]

Answer:

$75

Step-by-step explanation:

If it costs $25 for two hours and we want 6 hours, we simply multiply it by 3 because 6/2 = 3.

$25 * 3 = $75

7 0
3 years ago
Read 2 more answers
10.
Kay [80]

Answer:

\frac{(82)(2.4)^2}{104.139} \leq \sigma^2 \leq \frac{(82)(2.4)^2}{62.132}

4.535 \leq \sigma^2 \leq 7.602

Now we just take square root on both sides of the interval and we got:

2.2 \leq \sigma \leq 2.8

And the best option would be:

A.  2.2 < σ < 2.8

Step-by-step explanation:

Information provided

\bar X=32.1 represent the sample mean

\mu population mean  

s=2.4 represent the sample standard deviation

n=83 represent the sample size  

Confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The degrees of freedom are given by:

df=n-1=83-1=82

The Confidence is given by 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, the critical values for this case are:

\chi^2_{\alpha/2}=62.132

\chi^2_{1- \alpha/2}=104.139

And replacing into the formula for the interval we got:

\frac{(82)(2.4)^2}{104.139} \leq \sigma^2 \leq \frac{(82)(2.4)^2}{62.132}

4.535 \leq \sigma^2 \leq 7.602

Now we just take square root on both sides of the interval and we got:

2.2 \leq \sigma \leq 2.8

And the best option would be:

A.  2.2 < σ < 2.8

3 0
3 years ago
Multiply the fractions:<br> 2 / 5 ∙ 3 / 4.
Bingel [31]

Answer:

\frac{3}{10}

Step-by-step explanation:

\frac{2}{5} * \frac{3}{4} can be solved by just multiplying the numerators together and the denominators together

2 * 3 = 6 and 5 * 4 = 20 so the answer would be \frac{6}{20}

This simplifies to \frac{3}{10}

4 0
3 years ago
7652 divided by 12.3
Lady_Fox [76]

Answer:

The answer to the question provided is 622.1138211.

Rounded to the nearest tenth is 622.1

3 0
2 years ago
A. g(x)=3x^2<br> b. g(x)=(1/9x)^2<br> c. g(x)-1/3x^2<br> d. g(x)(1/3x)2
zaharov [31]

Answer:

the awnser would be a(g(x)=3x2

6 0
3 years ago
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