PLS HELP ME ASAP I AM TIMED explain ur asnwer DONT GUESS THATS REALLY IMMATURE AND RUDE

Y_(1)=3(5x-9)-3,y_(2)=8(x-5)+15,y_(1)=y_(2)

sammy [17]

Answer:

y2=8x−5y1=8x−25

Step-by-step explanation:

6 0

1 year ago

Enya is building a storage cupboard in the shape of a rectangular prism. The rectangular prism has a square base with side lengt

grin007 [14]

What do you think is the first step

4 0

3 years ago

All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be

Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a student is proficient in reading but not mathematics and $A \cap B$ is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

$B = b + (A \cap B)$

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

$(A \cup B) + C = 1$

In which

$(A \cup B) = a + b + (A \cap B)$

65% were found to be proficient in both reading and mathematics.

This means that $A \cap B = 0.65$

78% were found to be proficient in mathematics

This means that $B = 0.78$

$B = b + (A \cap B)$

$0.78 = b + 0.65$

$b = 0.13$

85% of the students were found to be proficient in reading

This means that $A = 0.85$

$A = a + (A \cap B)$

$0.85 = a + 0.65$

$a = 0.20$

Proficient in at least one:

$(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98$

What is the probability that the student is proficient in neither reading nor mathematics?

$(A \cup B) + C = 1$

$C = 1 - (A \cup B) = 1 - 0.98 = 0.02$

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0

3 years ago

What is the simplified form of V 100x35 ?

ElenaW [278]

Answer:

answer is 3500.

answer is 3500

7 0

3 years ago

A rectangular park had a perimeter of 18 miles. It is 7 miles wide. What is the area of the park?

4vir4ik [10]

Perimeter = 18 miles
Perimeter = 2a + 2b
2a + 2b = 18

a = ?
b = 7

18 = 2a + 2*7
18 = 2a + 14
2a = 18 - 14
2a = 4
a = 2

Area = a * b
Area = 2 * 7 = 14 miles2

7 0

3 years ago