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3 years ago

7

The cost of 8 kg of butter is $ 904. what will be the cost of 14 kg of butter

1 answer:

kvv77 [185]3 years ago

6 0

Answer:

$1582

Step-by-step explanation:

cost of each kg 904/8=113

cost of 14 kg 113x14=1582

the cost of 14 kg of butter is $1582

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Tourists from a tour bus were asked about places they visited during their stay in a city. The results are shown in the table.

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<span>Given:

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Rainbow [258]

Answer:

$\sin L = 0.60$

$tan\ N = 1.33$

$\cos L = 0.80$

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Step-by-step explanation:

Given

See attachment

From the attachment, we have:

$MN = 6$

$LN = 10$

First, we need to calculate length LM,

Using Pythagoras theorem:

$LN^2 = MN^2 + LM^2$

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Collect Like Terms

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$\sin L = \frac{Opposite}{Hypotenuse}$

$\sin L = \frac{MN}{LN}$

Substitute values for MN and LN

$\sin L = \frac{6}{10}$

$\sin L = 0.60$

Solving (b): $tan\ N$

$tan\ N = \frac{Opposite}{Adjacent}$

$tan\ N = \frac{LM}{MN}$

Substitute values for LM and MN

$tan\ N = \frac{8}{6}$

$tan\ N = 1.33$

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$\cos L = \frac{Adjacent}{Hypotenuse}$

$\cos L = \frac{LM}{LN}$

Substitute values for LN and LM

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$\cos L = 0.80$

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$\sin N = \frac{Opposite}{Hypotenuse}$

$\sin N = \frac{LM}{LN}$

Substitute values for LM and LN

$\sin N = \frac{8}{10}$

$\sin N = 0.80$

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Step-by-step explanation:

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