Let's solve this system of equations through substitution.
We have these two equations.
-7x-2y=14
6x+6y=18
Now let divide the second equation by 6.
6x+6y=18 ----> x+y=3
Next, let us move y to the right side of the equation.
x+y=3 -------> x=3-y (x equals 3-y)
Because we found out that what x is in terms of y, we can input that in for every instance of x in this equation below.
-7x-2y=14 becomes -7(3-y)-2y=14 (Why? Because x equals 3-y!)
We have a one variable equation now and can solve for y.
-7(3-y)-2y=14
-21+7y-2y=14
5y=35
y=7
Plug in 7 for y in any equation to find x.
x+y=3
x+7=3
x=-4
answer: x=-4, y=7
Answer:
x = 1 and x = -1
Step-by-step explanation:
Next time, please separate the equations with a comma or semicolon. Thanks.
We can substitute 4x for y in the quadratic equation x^2 + y^2=17:
x² + (4x)²=17.
Then x² + 16x² = 17, or
17x² = 17, or x² = 1. There are two solutions: x = 1 and x = -1.
You are essentially asking at this point where is the quadratic function greater than 0. To get the interval find the roots. Between the roots the function is guaranteed to be LESS THAN zero. Everywhere else the function is greater than 0.
Use Vieta's rule to get the roots,
Both roots are the same so no value is less than 0 which means all values except at the point of root are strictly greater, the point of root is at 
which means the set for which the quadratic function is greater than 0 is 
"all real numbers except 1".
To convert this into interval notation use all numbers up to 1 but not including and all numbers after 1 but not including,
Hope this helps :)
-2 could not be the answer to |2x - 0.6| because it would have to be positive due to the “| |” symbols.
