Answer:
The expected number of agents who receive between 2 and 5 calls is 5.
Step-by-step explanation:
An uniform probability is a case of probability in which each outcome is equally as likely.
For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.
The probability that we find a value X between c and d, d greater than c, is given by the following formula.

Uniformly distributed between 0 and 6 calls.
This means that 
Percentage of agents who receive between 2 and 5 calls.

If the center has 10 independent agents, what is the expected number of agents who receive between 2 and 5 calls
Independent, each one with a 0.5 probability. So
10*0.5 = 5
The expected number of agents who receive between 2 and 5 calls is 5.