Match the event with the most appropriate probability word: The roll of a normal fair dice will show a 7.

What type of triangle is formed by joining the points D(7, 3), E(8, 1), and

KiRa [710]

D(7, 3), E(8, 1), and F(4, -1)

We calculate the squared distances between the points:

$DE^2 = 1^2 + 2^2 = 5$

$EF^2=4^2+2^2=20$

$DF^2=3^2+4^2=25$

Since $DF^2=DE^2+EF^2$ we have a right triangle with hypotenuse DF.

7 0

3 years ago

HELP When 2((Three-fifths x + 2 and three-fourths y minus one-fourth x minus 1 and one-half y + 3)) is simplified, what is the r

lesya692 [45]

Answer:

<h2> StartFraction 7 over 10 EndFraction x + 2 and one-half y + 6</h2>

Step-by-step explanation:

Given the expression $2(\frac{3x}{5}+2\frac{3y}{4}-\frac{x}{4}-1 \frac{1}{2}y+3)$

To simplify the expression, we need to first collect the like terms of the functions in parentheses as shown;

$= 2(\frac{3x}{5}-\frac{x}{4}-1 \frac{1}{2}y+2\frac{3}{4}y+3)\\= 2(\frac{3x}{5}-\frac{x}{4}- \frac{3}{2}y+\frac{11}{4}y+3)\\$

Then we find the LCM of the resulting function

$= 2(\frac{3x}{5}-\frac{x}{4}- \frac{3}{2}y+\frac{11}{4}y+3)\\= 2(\frac{12x-5x}{20} - (\frac{6y-11y}{4})+3)\\= 2(\frac{7x}{20}- (\frac{-5y}{4})+3 )\\= 2(\frac{7x}{20}+ \frac{5y}{4}+3 )\\= \frac{7x}{10} + \frac{5y}{2} +6\\= \frac{7x}{10} + 2\frac{1}{2}y+6\\$

The final expression gives the required answer

7 0

2 years ago

PLSS HELP

Dmitry [639]

Answer:

$8,000

Step-by-step explanation:

Let the store earned $x in December.

Therefore,

Money spent to buy new inventory $=\frac{1}{4} x$

Remaining money $= x - \frac{1}{4} x =\frac{3}{4} x$

Money used to pay bills $=\frac{1}{2} \times \frac{3}{4} x=\frac{3}{8} x$

Money still left over = $3,000

Total money earned in December $= \frac{1}{4} x+ \frac{3}{8} x+3,000$

$\therefore x= \frac{1}{4} x+ \frac{3}{8} x+3,000$

$\therefore x= \frac{2}{8} x+ \frac{3}{8} x+3,000$

$\therefore x= \frac{5}{8} x+ 3,000$

$\therefore x- \frac{5}{8} x=3,000$

$\therefore \frac{8x-5x}{8} =3,000$

$\therefore \frac{3x}{8} =3,000$

$\therefore x =3,000\times \frac {8}{3}$

$\therefore x =1,000\times 8$

$\therefore x =\$8,000$

Thus, total money earned in December is $8,000.

3 0

2 years ago

What is the interquartile range (IQR) of the following data set 17 16 21 15 25 22 18 23 17

Pepsi [2]

IQR = 6

First locate the median $Q_{2}$ at the centre of the data arranged in ascending order. Then locate the lower and upper quartiles $Q_{1}$ and $Q_{3}$ located at the centre of the data to the left and right of the median.