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Vinvika [58]
3 years ago
13

Find the product. state your answer in standard form (x+7)(x squared + 6x - 8)

Mathematics
2 answers:
USPshnik [31]3 years ago
6 0

Answer:

{x}^{3}  +  13 {x}^{2}   + 34x  - 56

Step-by-step explanation:

(x + 7)( {x}^{2}  + 6x - 8) \\  = x ( {x}^{2}  + 6x - 8)  +  7( {x}^{2}  + 6x - 8)  \\  =  {x}^{3}  + 6 {x}^{2}  - 8x + 7 {x}^{2}  + 42x - 56 \\  = {x}^{3}  +  6 {x}^{2}  + 7 {x}^{2} + 42x - 8x - 56 \\  = {x}^{3}  +  13 {x}^{2}   + 34x  - 56 \\

astraxan [27]3 years ago
6 0

Answer:

x^3+13x^2-34x-56

Step-by-step explanation:

x(x^2+6x-8)+7(x^2+6x-8)

x^3+6x^2+-8x+7x^2+42-56

add or subtract like terms but before i do that i arrange them

x^3+6x^2+7x^2-8x+42x-56

x^3+13x^2-34x-56

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According Two data from the 2010 United States Census 83.7% of Americans lived in the metropolitan area suppose maria researcher
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Answer:

Mean is 83.7%

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Step-by-step explanation:

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Let us assume the P be the sample proportion

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3 years ago
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ser-zykov [4K]

Answer:

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Step-by-step explanation:

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3 years ago
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(a) Show that the volume of a metal sphere of radius 15 cm is 14140 cm”, correct to 4 significant
Sladkaya [172]

Answer:

a) The volume of the sphere is approximately 14,137.16694 which is 14,140 cm³ correct to 4 significant figures

b) The volume of water required to fill the tank is approximately 103,670 cm³

Step-by-step explanation:

a) In the question, the radius of the sphere, r = 15 cm

The formula for the volume, 'V', of a sphere is given as follows;

V = \dfrac{4}{3} \times \pi \times r^3

Where;

r = The radius of the the sphere

V = The volume of the sphere

Plugging in the value for the radius, 'r', of the sphere, in the equation for, 'V', we get;

V = \dfrac{4}{3} \times \pi \times 15^3 \approx = 14,137.16694

Therefore;

The volume of the sphere to 4 significant figures is V ≈ 14,140 cm³

b) The parameters of the cylindrical tank are;

The height of the cylindrical tank, h = 60 cm

The radius of the cylindrical tank, r = 25 cm

The volume of a cylinder, V = π·r²·h

∴ The volume of the cylindrical tank without water, 'V_t', is given as follows;

V_t = π × (25 cm)² × 60 cm ≈ 117809.72451 cm³

The volume of water, V_{water}, required to fill the tank with the sphere of volume 'V' placed inside is given as follows

V_t = V + V_{water}

∴ V_{water} = V_t - V

From which we get;

V_{water} ≈ 117809.72451 cm³ - 14,140 cm³ = 103,669.72451 cm³ ≈ 103,670 cm³

The volume of water required to fill the tank, V_{water} ≈ 103,670 cm³.

8 0
3 years ago
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