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Len [333]
3 years ago
7

Find the matrices of ​

Mathematics
1 answer:
aniked [119]3 years ago
8 0

\huge{\sf \left[{x-2y\atop 6x-2z}\:\:\:{4y-3\atop 2y-z}\right]=\left[{-3\atop 4}\:\:\:{5\atop 3}\right]}

Creating equations

\\ \sf\longmapsto x-2y=-3\dots(1)

\\ \sf\longmapsto 4y-3=5\dots(2)

\\ \sf\longmapsto 6x-2z=4\dots(3)

\\ \sf\longmapsto 2y-z=3\dots(3)

  • From eq(2)

\\ \sf\longmapsto 4y-3=5

\\ \sf\longmapsto 4y=5+3

\\ \sf\longmapsto 4y=8

\\ \sf\longmapsto y=\dfrac{8}{4}

\\ \bf\longmapsto y=2

  • Put the value in eq(1)

\\ \sf\longmapsto x-2y=-3

\\ \sf\longmapsto x=-3+2y

\\ \sf\longmapsto x=-3+2(2)

\\ \sf\longmapsto x=-3+4

\\ \bf\longmapsto x=1

  • Put the value in eq(4)

\\ \sf\longmapsto 2y-z=3

\\ \sf\longmapsto z=2y-3

\\ \sf\longmapsto z=2(2)-3

\\ \sf\longmapsto z=4-3

\\ \bf\longmapsto z=1

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F=f (1-v/s) change the subject of the formula into v
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Changing the subject of the formula into v means expressing v in terms of the other given variables. So given the original equation, as shown below, we can rearrange it so that we have v isolated on one side.

F = f(1 - \frac{v}{s})
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To isolate v, we can just multiply s to both sides and come up with the final equation below.

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Thus, we have v = s(1 - F/f) with v as the subject of the formula.

Answer: v = s(1 - F/f)
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