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Naddik [55]
3 years ago
10

13.) Springfield Elementary is putting on a school play

Mathematics
1 answer:
Oduvanchick [21]3 years ago
3 0

45 adult tickets and 80 children tickets were sold

<em><u>Solution:</u></em>

Let "a" be the number of adult tickets sold

Let "c" be the number of children tickets sold

Cost of 1 adult ticket = $ 6

Cost of 1 children ticket = $ 3.50

<em><u>They sold a total of 125 tickets</u></em>

Therefore,

a + c = 125

c = 125 - a --------- eqn 1

<em><u>They made a total of $550. Therefore, frame a equation as:</u></em>

number of adult tickets sold x Cost of 1 adult ticket + number of children tickets sold x Cost of 1 children ticket = 550

a \times 6 + c \times 3.50 = 550\\

6a + 3.50c = 550 ----------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

<em><u>Substitute eqn 1 in eqn 2</u></em>

6a + 3.50(125 - a) = 550

6a + 437.5 - 3.50a = 550

2.5a = 112.5

<h3>a = 45</h3>

<em><u>Substitute a = 45 in eqn 1</u></em>

c = 125 - 45

<h3>c = 80</h3>

Thus 45 adult tickets and 80 children tickets were sold

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