Answer:
Explanation:
#include <stdio.h>
int main(void)
{
int num, rem;
printf("Enter a number: ");
scanf("%d", &num);
printf("Roman numerals: ");
while(num != 0)
{
if (num >= 1000) // 1000 - m
{
printf("m");
num -= 1000;
}
else if (num >= 900) // 900 - cm
{
printf("cm");
num -= 900;
}
else if (num >= 500) // 500 - d
{
printf("d");
num -= 500;
}
else if (num >= 400) // 400 - cd
{
printf("cd");
num -= 400;
}
else if (num >= 100) // 100 - c
{
printf("c");
num -= 100;
}
else if (num >= 90) // 90 - xc
{
printf("xc");
num -= 90;
}
else if (num >= 50) // 50 - l
{
printf("l");
num -= 50;
}
else if (num >= 40) // 40 - xl
{
printf("xl");
num -= 40;
}
else if (num >= 10) // 10 - x
{
printf("x");
num -= 10;
}
else if (num >= 9) // 9 - ix
{
printf("ix");
num -= 9;
}
else if (num >= 5) // 5 - v
{
printf("v");
num -= 5;
}
else if (num >= 4) // 4 - iv
{
printf("iv");
num -= 4;
}
else if (num >= 1) // 1 - i
{
printf("i");
num -= 1;
}
}
return 0;
}
A method of transformation that involves changing the radix or base of the original key and either discarding excess high-order digits (that is, digits in excess of the number desired in the key) or extracting some part of the transformed number.
It is b,<span>dialogue it's speech between characters, and there are no characters and functional text </span>
Answer:
Option C is correct.
Explanation:
When the supply of system engineers rises while demand for such workers falls at the similar period, Wages will drop while competition for employment rises.
According to the law of demand, when the supply of one commodity is increased then the demand for other commodity falls. So, the following option C is correct according to the following scenario.
Other options are incorrect because they are not relevant according to the following scenario.
