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____ [38]
3 years ago
12

What is the domain of the square root function graphed below?

Mathematics
2 answers:
mina [271]3 years ago
7 0

Answer:

D

Step-by-step explanation:

because its right

fiasKO [112]3 years ago
3 0

Answer:

The domain is [3,\infty).

Step-by-step explanation:

Domain is the input to a function. The input to a function is marked along the x axis as the x values are the independent values and thus are in the domain of the function.

From the graph, the function starts at x = 3 when the point is (3,1) and then the graph of the moves towards infinity.

So, the domain of the function starts at 3 and move towards infinity.

Hence, the domain include the x values between 3 to infinity including 3.

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Find the mean absolute deviation of the data: 5,8,8,10,13,14,16,22
Rama09 [41]

Answer:

7

Step-by-step explanation:

ghj

4 0
3 years ago
Is there a way to simplify the process of plugging in factors through synthetic division to find the zeros of a polynomial? I am
Iteru [2.4K]
Yes you can use the discriminant of a quadratic/polynomial. For instance, if
b^2 - 4ac = 0 there is one real root. If b^2 - 4ac > 0 there are two real roots and ib^2 - 4ac < 0  there are no real roots

The discriminant comes from the quadratic equation, which is the following.
x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}
4 0
3 years ago
Axis of sym: x =
marta [7]

Answer:

<h2>SEE BELOW</h2>

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • quadratic function
  • PEMDAS
<h3>let's solve:</h3>

vertex:(h,k)

therefore

vertex:(-1,4)

axis of symmetry:x=h

therefore

axis of symmetry:x=-1

  • to find the quadratic equation we need to figure out the vertex form of quadratic equation and then simply it to standard form i.e ax²+bx+c=0

vertex form of quadratic equation:

  • y=a(x-h)²+k

therefore

  • y=a(x-(-1))²+4
  • y=a(x+1)²+4

it's to notice that we don't know what a is

therefore we have to figure it out

the graph crosses y-asix at (0,3) coordinates

so,

3=a(0+1)²+4

simplify parentheses:

3 = a(1 {)}^{2}  + 4

simplify exponent:

3 =  a + 4

therefore

a =  - 1

our vertex form of quadratic equation is

  • y=-(x+1)²+4

let's simplify it to standard form

simplify square:

y =  - ( {x}^{2}  + 2x + 1)  + 4

simplify parentheses:

y =  -  {x}^{2}  - 2x - 1 + 4

simplify addition:

y =  -  {x}^{2}  - 2x + 3

therefore our answer is D)y=-x²-2x+3

the domain of the function

x\in \mathbb{R}

and the range of the function is

y\leqslant 4

zeroes of the function:

-  {x}^{2}  - 2x + 3 = 0

\sf divide \: both \: sides \: by \:  - 1

{x}^{2}  + 2x - 3 = 0

\implies \:  {x}^{2} +   3x  - x  +  3 = 0

factor out x and -1 respectively:

\sf \implies \: x(x + 3)   - 1(x  + 3 )= 0

group:

\implies \: (x - 1)(x + 3) = 0

therefore

\begin{cases} x_{1} = 1 \\  x_{2}  =  - 3\end{cases}

4 0
3 years ago
Triangle A″B″C″ is formed using the translation (x + 2, y + 0) and the dilation by a scale factor of one half from the origin. W
Travka [436]

Complete question:

Triangle A″B″C″ is formed using the translation (x + 2, y + 0) and the dilation by a scale factor of one half from the origin. Which equation explains the relationship between segment AB and segment A double prime B double prime?

A) segment a double prime b double prime = segment ab over 2

B) segment ab = segment a double prime b double prime over 2

C) segment ab over segment a double prime b double prime = one half

D) segment a double prime b double prime over segment ab = 2

Answer:

A) segment a double prime b double prime = segment ab over 2.

It can be rewritten as:

A"B" = \frac{AB}{2}

Step-by-step explanation:

Here, we are given triangle A″B″C which was formed using the translation (x + 2, y + 0) and the dilation by a scale factor of one half from the origin.

We know segment A"B" equals segment AB multiplied by the scale factor.

A"B" = AB * s.f.

Since we are given a scale factor of ½

Therefore,

A"B" = AB * \frac{1}{2}

A"B" = \frac{AB}{2}

The equation that explains the relationship between segment AB and segment A"B" is

A"B" = \frac{AB}{2}

Option A is correct

5 0
3 years ago
Write each phrase as an algebraic expression.<br> 16 seconds faster than Aya’s time.
Anna35 [415]

Given:

The given phrase is 16 seconds faster than Aya’s time.

To find:

The algebraic expression for the given phrase.

Solution:

Let x be the Aya’s time.

16 seconds faster than Aya’s time. It means 16 seconds less than Aya’s time.

We know that a negative sign "-" is used for less than.

16 seconds less than Aya’s time = x-16

16 seconds faster than Aya’s time = x-16

Therefore, the required algebraic expression is x-16.

8 0
3 years ago
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