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qaws [65]
3 years ago
6

9. Carlos is taking a road trip. So far he has traveled 120 miles at a constant speed of 60 mph. His

Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
3 0

Answer:

Part 1) 300 miles

Part 2) 420 miles

Part 3) 600 miles

Step-by-step explanation:

we have

d(x)=60x+120

where

d(x) is the distance in miles

x is the time in hours

Part 1) How many miles  will he have traveled after 3 more hours?

we know that

To find the distance, substitute the value of x in the function

so

For x=3 hours

d(3)=60(3)+120=300\ mi

For x=3, d(x)=300

That means -----> After 3 hours Carlos has traveled 300 miles at a constant speed of 60 mph

Part 2) How many miles  will he have traveled after 5 more hours?

we know that

To find the distance, substitute the value of x in the function

so

For x=5 hours

d(5)=60(5)+120=420\ mi

For x=5, d(x)=420

That means -----> After 5 hours Carlos has traveled 420 miles at a constant speed of 60 mph

Part 3) How many miles  will he have traveled after 8 more hours?

we know that

To find the distance, substitute the value of x in the function

so

For x=8 hours

d(8)=60(8)+120=600\ mi

For x=8, d(x)=600

That means -----> After 8 hours Carlos has traveled 600 miles at a constant speed of 60 mph

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3 years ago
A number, y, is equal to twice the sum of a smaller number and 3. The larger number is also equal to 5 more than 3 times the sma
RSB [31]

Answer:

A.

Step-by-step explanation:

<em>NOTE: The "larger number" will be referred to as y, and the "smaller number" will be referred to as x.</em>

"A number, y, is equal to twice the sum of a smaller number and 3."

This tells us that we must add our smaller number (x) to 3 within parantheses and then multiply the entire term (x+3) by 2.

y=2(x+3)

"The larger number is also equal to 5 more than 3 times the smaller number."

This tells us that we must multiply 3 against our smaller number (x) and add 5 to it.

y=3x+5

Now, to find your answer, we can put the equations in the same form as the answer choices so as to find an equivalent equation. Lets start with the first equation.

This form calls for us to have our x term first, then our y term, then our constant.

y=2(x+3)\\y=2x+6\\-2x+y=6

Now that we've gotten the equation in that form, we can see that our answer choices hold that our leading co-efficient must be positive, which we can adjust for by dividing both sides by -1.

-2x+y=6\\2x-y=-6

This makes the only possible answer choices (A) and (C).

Now, lets do our second equation. The recipe calls for the same form, again with a positive leading coefficient.

y=3x+5\\-3x+y=5\\3x-y=-5

This is only represented by choices (A) and (B).

Therefore, answer choice (A) is the only one which represents both equations.

7 0
3 years ago
Find the x-intercepts for the parabola defined by the equation below. y = x2 + 9x + 14
faltersainse [42]

Answer:

x - intercepts are (-7,0) and (-2,0)

A is the correct option.

Step-by-step explanation:

We have been given the equation of the parabola y=x^2+9x+14

For x- intercept, y = 0

0=x^2+9x+14

We can split the middle term as 9x = 7x +2x

x^2+7x+2x+14=0

Now take GCF

x(x+7)+2(x+7)=0

Factored out the common term

(x+7)(x+2)=0

Apply the zero product property

(x+7)=0,(x+2)=0

Solve for x

x=-7,-2

Hence, x - intercepts are (-7,0) and (-2,0)

A is the correct option.

4 0
3 years ago
ABC was dilated to create A' B' C'. What is the center of dilation? And what is the scale factor of the dilation?
Virty [35]

Given:

In the given figure the vertices of triangle ABC are A(-2,2), B(4,2), C(-2,-2).

The vertices of triangle A'B'C' are A'(-4,4), B'(8,4), C'(-4,-4).

To find:

The center of dilation and the scale factor.

Solution:

In the given graph, draw the lines AA', BB' and CC'. The intersection point of these lines is the center of dilation.

From the below graph, it is clear that the lines AA', BB' and CC' intersect each other at (0,0).

Therefore, the center of dilation is (0,0).

If a figure is dilated by factor k and the center of dilation is origin, then

(x,y)\to (kx,ky)

A(-2,2)\to A'(k(-2),k(2))

A(-2,2)\to A'(-2k,2k)

It is given that A'(-4,4). So,

(-2k,2k)=(-4,4)

On comparing both sides, we get

-2k=-4

2k=4

k=\dfrac{4}{2}

k=2

Therefore, the scale factor is 2.

4 0
3 years ago
What is the solution to this equation? ​
slamgirl [31]

Answer: No solution.

Step-by-step explanation:

1. The lines are parallel.

2. If you solve the system of equations you would end up with 0x, so you cannot solve for x.

4 0
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