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3 years ago

Please help. What do I do

Mathematics

1 answer:

Marina86 [1]3 years ago

6 0

1. let x = a number

x^2+5

2. let x = a number

2x-(x+19)

3. let x = a number

2x=1/3x + 9

4. let x = 1st integer

x+1 = 2nd integer

x+2 = 3rd integer

(x+x+1+x+2)/4

=(3x+3)/4

5. let x=smallest integer

x+1 = 2nd integer

x+2 = 3rd integer

x+3 = largest integer

x+x+1+x+2+x+3 = 9(x+3)

= 4x+6= 9x+27

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Natural numbers are all whole numbers from 1 to infinity. i.e

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These numbers are all natural numbers including their negative counterparts (i.e negatives of the natural numbers) and also 0.

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1 is a natural number as well as an integer

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3 root 12 (written as $3\sqrt{12}$ ) is neither a natural nor an integer number.

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