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Gennadij [26K]
3 years ago
9

Determine the zero of F(x)=x^2+3x-5

Mathematics
1 answer:
IgorLugansk [536]3 years ago
3 0

Answer:

The answer to your question is:

Step-by-step explanation:

                                             x² + 3x - 5

                                    x² + 3x + (3/2)² = 5 + (3/2)²

                                         (x + 3/2)² = 5 + 9/4

                                         (x + 3/2)² = (20 + 9) /4

                                          (x + 3/2)² = 29/4

                                          x + 3/2 = ±√29 / 2

                                     

x 1 = -3/2 + √29/2                               x2 = -3/2 - √29/2

x1 = 1.19                                                x2 = -4.19

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Please help! Quick!
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Read 2 more answers
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