3 years ago

Determine the zero of F(x)=x^2+3x-5

Mathematics

1 answer:

IgorLugansk [536]3 years ago

3 0

Answer:

The answer to your question is:

Step-by-step explanation:

x² + 3x - 5

x² + 3x + (3/2)² = 5 + (3/2)²

(x + 3/2)² = 5 + 9/4

(x + 3/2)² = (20 + 9) /4

(x + 3/2)² = 29/4

x + 3/2 = ±√29 / 2

x 1 = -3/2 + √29/2 x2 = -3/2 - √29/2

x1 = 1.19 x2 = -4.19

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