At point of intersection the two equations are equal,
hence, 6x³ =6x²
6x³-6x²=0
6x²(x-1)=0 , the values of x are 0 and 1
The points of intersection are therefore, (0,0) and (1,6)
To find the slopes of the tangents at the points of intersection we find dy/dx
for curve 1, dy/dx=12x, and the other curve dy/dx=18x²
At x=0, dy/dx=12x =0, dy/dx=18x² = 0, hence the angle between the tangents is 0, because the tangents to the two curves have the same slope which is 0 and pass the same point (0,0) origin.
At x=1, dy/dx =12x = 12, dy/dx= 18x² =18, Hence the angle between the two tangents will be given by arctan 18 -arctan 12
= 86.8202 - 85.2364 ≈ 1.5838, because the slope of the lines is equal to tan α where α is the angle of inclination of the line.
Answer:
7h
Step-by-step explanation:
(1) Outcomes
(2) Permutation
(3) Tree Diagram
(4) Counting Principle
(5) Combination
(6) Factorial
(7) Addition Principle of Counting
(8) Multiplication Principle of Counting
<em>Hope this helps</em>
<em>-Amelia The Unknown</em>
9/50 is the answer I think!
I converted 9/10 to decimal to make it easier for me to solve and got 0.9
I divided 0.9 by 5 and got 0.18
I converted 0.18 to fraction and got 9/50
