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torisob [31]
3 years ago
8

Please answer this for me :)

Mathematics
2 answers:
atroni [7]3 years ago
8 0

Answer:

d = 1.5

Step-by-step explanation:

yes

vlabodo [156]3 years ago
8 0

Answer:

1.5

Step-by-step explanation:

First put like terms on one side:

-3/8d - 1/2d = -11/16 - 5/8

then make the demominators the same:

-3/8d - 4/8d = -11/16 - 10/16

add up the terms:

-7/8d = -21/16

solve for d:

d= 1.5

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Someone can you please help me on number 74
lisabon 2012 [21]

Answer:

  9t^3 +t^2

Step-by-step explanation:

The perimeter of the figure is the sum of the lengths of the sides. The side lengths are represented by the polynomials shown, so the perimeter (P) is their sum:

  P = (4t^3 -5) + (4t^3 -5) + (t^2 +9) + (t^3 -t^2 -11) + (t^2 +12)

Rearranging to group like terms:

  P = (4t^3 +4t^3 +t^3) + (t^2 -t^2 +t^2) + (-5 -5 +9 -11 +12)

  P = 9t^3 +t^2

The perimeter of the figure is represented by the polynomial 9t^3 +t^2.

5 0
3 years ago
Read 2 more answers
Because Charles David Keeling and his new colleagues began measuring CO2 in 1958, we now have an excellent record of how CO2 con
Alecsey [184]

Answer:

1. 516 ppm; 2. 561 ppm

Step-by-step explanation:

1. CO₂ increase at old rate

Time = 2100 - 2010 = 90 years

Increase in CO₂ = 90 yr × (1.4 ppm/1 yr) = 126 ppm

CO₂ in 2010 = 390 + 126 = 516 ppm

At the old rate, the CO₂ concentration in 2100 will be 516 ppm.

2. CO₂ increase at new rate

Time = 2100 - 2010 = 90 years

Increase in CO₂ = 90 yr × (1.9 ppm/1 yr) = 171 ppm

CO₂ in 2010 = 390 + 171 = 561 ppm

At the new rate, the CO₂ concentration in 2100 will be 561 ppm.

6 0
2 years ago
What is the effect in the time required to solve a prob- lem when you double the size of the input from n to 2n, assuming that t
Inga [223]

Answer:

f(2n)-f(n)=log2

b.lg(lg2+lgn)-lglgn

c. f(2n)/f(n)=2

d.2nlg2+nlgn

e.f(2n)/(n)=4

f.f(2n)/f(n)=8

g. f(2n)/f(n)=2

Step-by-step explanation:

What is the effect in the time required to solve a prob- lem when you double the size of the input from n to 2n, assuming that the number of milliseconds the algorithm uses to solve the problem with input size n is each of these function? [Express your answer in the simplest form pos- sible, either as a ratio or a difference. Your answer may be a function of n or a constant.]

from a

f(n)=logn

f(2n)=lg(2n)

f(2n)-f(n)=log2n-logn

lo(2*n)=lg2+lgn-lgn

f(2n)-f(n)=lg2+lgn-lgn

f(2n)-f(n)=log2

2.f(n)=lglgn

F(2n)=lglg2n

f(2n)-f(n)=lglg2n-lglgn

lg2n=lg2+lgn

lg(lg2+lgn)-lglgn

3.f(n)=100n

f(2n)=100(2n)

f(2n)/f(n)=200n/100n

f(2n)/f(n)=2

the time will double

4.f(n)=nlgn

f(2n)=2nlg2n

f(2n)-f(n)=2nlg2n-nlgn

f(2n)-f(n)=2n(lg2+lgn)-nlgn

2nLg2+2nlgn-nlgn

2nlg2+nlgn

5.we shall look for the ratio

f(n)=n^2

f(2n)=2n^2

f(2n)/(n)=2n^2/n^2

f(2n)/(n)=4n^2/n^2

f(2n)/(n)=4

the time will be times 4 the initial tiote tat ratio are used because it will be easier to calculate and compare

6.n^3

f(n)=n^3

f(2n)=(2n)^3

f(2n)/f(n)=(2n)^3/n^3

f(2n)/f(n)=8

the ratio will be times 8 the initial

7.2n

f(n)=2n

f(2n)=2(2n)

f(2n)/f(n)=2(2n)/2n

f(2n)/f(n)=2

5 0
2 years ago
beginning at sea level a scuba diver dove 1 2/3 feet into the water , and then dove an additional 3 2/5 feet at what elevation i
skad [1K]

The given details are illustrations of addition and subtractions of fractions.  The scuba driver is at an elevation of -5\frac{1}{15} ft below the sea  level.

Given that:

n_1 = 1\frac 23 --- the first dive

n_2 = 3\frac 25 ---- the additional dive

From the question, we understand that the diver starts at the sea level.

This is represented with 0ft.

So, the diver's elevation (d) is calculated as follows:

d = 0 - n_1 - n_2 --- we use subtraction because the diver is below the sea level

So, we have:

d = 0 - 1\frac 23 - 3\frac 25

d = - 1\frac 23 - 3\frac 25

Convert fractions

d = - \frac 53 - \frac{17}5

Take LCM

d = \frac{-5 \times 5 - 17 \times 3}{15}

d = \frac{-76}{15}

Reduce fraction

d = -5\frac{1}{15}

The above value means that the diver's elevation is at -5\frac{1}{15} ft below the sea  level.

Read more about fractions at:

brainly.com/question/18134643

5 0
3 years ago
HELP ME A.S.A.P. PLZZZZ
Ronch [10]

Answer:

A = 66.5 in²

Step-by-step explanation:

There are a few different equations to find the area of a rhombus.  If you are given the measurements of the two diagonals, you can use the following formula:  

Area (A) = \frac{d_{1}d_{2} }{2}

Using this formula, you can multiply the measures of the diagonals and then divide by 2:

area = \frac{(9.5)(14)}{2} =\frac{133}{2}=66.5in^{2}

7 0
3 years ago
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