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2 years ago

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Someone plz help! thx

1 answer:

timurjin [86]2 years ago

6 0

Convert each mixed number to an improper fraction

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Convert 6&1/2 to an improper fraction

6&1/2 = (6*2+1)/2
6&1/2 = (12+1)/2
6&1/2 = 13/2
--------------------------------------------
Do the same for 9&1/4

9&1/4 = (9*4+1)/4
9&1/4 = (36+1)/4
9&1/4 = 37/4
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Now multiply the improper fractions 13/2 and 37/4. Multiply straight across

(13/2)*(37/4) = (13*37)/(2*4)
(13/2)*(37/4) = 481/8
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The last step is to use long division to find the mixed number equivalent of 481/8

Or we an say
60*8 = 480
So 60*8+1 = 480+1
which means
481/8 = (480+1)/8 = 480/8+1/8 = 60&1/8

Making the final answer to be choice C

Another way to get the answer is to convert 481/8 into a decimal to get 60.125 and then convert that back to a mixed number. You should get 60&1/8

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Which formula gives the x-coordinates of the maximum values for y = cos(x)?

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3 years ago

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3 years ago

The Martinez family went to the movies and paid $60 for two adult tickets and three children’s tickets. The Wright family consis

Pepsi [2]

Answer:

a = $13.5

Step-by-step explanation:

Let a = adult tickets

Let c = children tickets

Translating the word problem into an algebraic equation;

<u>For the Martinez family;</u>

2a + 3c = $60

<u>For the Wright family;</u>

3a + 5c = $95.5

Thus, the simultaneous equations are;

$2a + 3c = $60$ ..........equation 1

$3a + 5c = $95.5$ .........equation 2

We would use substitution method to solve;

From equation 2, we make a the subject of formula;

3a = 95.5 - 5c

a = (95.5 - 5c)/3

<em>Substituting the value of "a" into equation 1, we have;</em>

2[(95.5-5c)/3] + 3c = 60

Multiplying all through by 3;

2(95.5 - 5c) + 9c = 180

191 - 10c + 9c = 180

191 - c = 180

c = 191-180

c = $11

To find the value of a;

2a +3c = 60

<em>Substituting the value of "c" into the equation, we have;</em>

$2a + 3(11) = 60$

$2a + 33 = 60$

$2a = 60 - 33$

$2a = 27$

$a = \frac{27}{2}$

a = $13.5

<em>Therefore, the cost of an adult movie ticket is $13.5. </em>

5 0

2 years ago