For this question, we can assume that RS + ST = RT. So now, we just have to plug in the expressions for these lengths, and solve the equation.
(3x+1) + (2x-2) = 64
Because we are only dealing with one operation, the parentheses aren't necessary.
3x + 1 + 2x - 2 = 64
Next, we should combine like terms on the left side of the equation. We know that 3x + 2x = 5x, and that 1 - 2 = -1.
5x - 1 = 64
The goal of an equation is to get the variable alone. To do this, we have to get rid of the -1 on the left side of the equation. So, we are going to add 1 to both sides of the equation, to cancel out the -1 on the left side.
5x = 65
Finally, we are going to divide both sides by 5, as this is the inverse operation of multiplication, which is how the 5 and the x are connected.
x = 13
Therefore, the value of x is 13.
We are finding slope:
change in y / change in x
277 - 205 / 2007 - 1997
72 / 10
7.2
<h2 /><h2>
~ 7</h2><h2>
</h2>
Answer:
6:20 AM
Step-by-step explanation:
Answer:
(-2, -6)
Step-by-step explanation:
g(x) = (x+2)²-6
= x²+4x+4-6
= x²+4x-3
the vertex :
x = -4/2 = -2
y = (-2+2)²-6 =0-6 = -6
point of vertex : (-2, -6)
According to the direct inspection, we conclude that the best approximation of the two solutions to the system of <em>quadratic</em> equations are (x₁, y₁) = (- 1, 0) and (x₂, y₂) = (1, 2.5). (Correct choice: C)
<h3>What is the solution of a nonlinear system formed by two quadratic equations?</h3>
Herein we have two parabolae, that is, polynomials of the form a · x² + b · x + c, that pass through each other twice according to the image attached to this question. We need to estimate the location of the points by visual inspection on the <em>Cartesian</em> plane.
According to the direct inspection, we conclude that the best approximation of the two solutions, that is, the point where the two parabolae intercepts each other, to the system of two <em>quadratic</em> equations are (x₁, y₁) = (- 1, 0) and (x₂, y₂) = (1, 2.5). (Correct choice: C)
To learn more on quadratic equations: brainly.com/question/17177510
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