Answer:
A shaded region below a dashed line (y <3x-4)
Step-by-step explanation:
For linear inequalities, we have shaded regions below or above a dashed or solid or continuous line represented by an inequality.
Their graphs are called region graphs. Those regions are only enclosed ones if before the sign of inequality it is included both variables. Like x²+y²<1, |x+y|<1, etc.
In this case what we have here is an open region, as the graph below shows.
3x-y>4 =-y>4-3x∴y<3x-4
Setting a value for x
3x-4=0
3x=4
3x/3=4/3
x=4/3 (slope)
(4/3,0)
The answer is 4,000 ft squared because since the sides are 100 ft and 80ft then we need to multiply them which is 8,000 then divide that by 2 since it’s a triangle which is 4,000 ft squared.
-4g + 12 = 16 then -12 on the both side
-4g = 4 then divided by -4, you will get g = -1
Answer:
The true average mileage of the Libra Using Null hypothesis is as ;
H0:μ≤26
(Ha):μ >26
Step-by-step explanation:
Given:
Libra, will average better than 26 miles per gallon in the city
To Find:
Average mileage of the Libra.
Solution:
This problem is related to the null hypothesis and alternate hypothesis.
i.e Null Hypothesis is the statement which is true and statement which contradictory is called alternate hypothesis.
<em>“reject H0” if the sample information favors the alternative hypothesis.
</em>
<em>“do not reject H0” / “decline to reject H0” if the sample information is insufficient to reject the null hypothesis</em>
So given that condition is libra will have average better than 26
So it will include 26 and above values .
i.e. True condition is called as null hypothesis (H0)
so true average will be greater than 26
So H0:μ≤26
And the Alternate hypothesis will be the contradictory to true condition
(Ha):μ >26 .
<u>Answer:</u>
x = 7.5 km/h
<u>Step-by-step explanation:</u>
• First calculate the distance covered by walking at 3 km/h for 45 minutes ( 0.75 h):
distance = speed × time
= 3 × 0.75
= 2.25 km
• Therefore, she covered 2.25 km of the total journey by walking. Since she was 6 km from the starting point at the end of the entire journey, we can calculate the distance remaining, which she had to run:
distance she had to run = 6 - 2.25
= 3.75 km
• Now we can calculate the speed of the 30 minute (0.5 h) run:
speed = distance ÷ time
= 3.75 ÷ 0.5
= 7.5 km/h
This means that she ran at 7.5 km/h for half an hour.
∴ x = 7.5
