Answer:
hdhdhd
jdnffjfbjffbkfbfkfbfifoff
Known facts:
A line shaft rotating at 250 rpm, a grinder shaft that turns at 1200 rpm diameter of grinder pulley is 5 inches.
1. Proportion equation
350/1200 = 5/x
2. Cross multiply
1200*5=250*x
x=(1200*5)/250 = (24*50*5)/(5*50) = 24
The big wheel diameter is 24 inches
Answer:
iba nalang
Step-by-step explanation:
just tell someting wag yan
Answer:
13.5
Step-by-step explanation:
12/4=3
9/3=3
4.5x3=13.5
Let's call the stamps A, B, and C. They can each be used only once. I assume all 3 must be used in each possible arrangement.
There are two ways to solve this. We can list each possible arrangement of stamps, or we can plug in the numbers to a formula.
Let's find all possible arrangements first. We can easily start spouting out possible arrangements of the 3 stamps, but to make sure we find them all, let's go in alphabetical order. First, let's look at the arrangements that start with A:
ABC
ACB
There are no other ways to arrange 3 stamps with the first stamp being A. Let's look at the ways to arrange them starting with B:
BAC
BCA
Try finding the arrangements that start with C:
C_ _
C_ _
Or we can try a little formula; y×(y-1)×(y-2)×(y-3)...until the (y-x) = 1 where y=the number of items.
In this case there are 3 stamps, so y=3, and the formula looks like this: 3×(3-1)×(3-2).
Confused? Let me explain why it works.
There are 3 possibilities for the first stamp: A, B, or C.
There are 2 possibilities for the second space: The two stamps that are not in the first space.
There is 1 possibility for the third space: the stamp not used in the first or second space.
So the number of possibilities, in this case, is 3×2×1.
We can see that the number of ways that 3 stamps can be attached is the same regardless of method used.
