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3 years ago

Can I have some help with this? Construct a linear function that has a slope of -3 and passes through the point (-2,3).

Mathematics

1 answer:

Arisa [49]3 years ago

4 0

Answer:

-3x-3

Step-by-step explanation:

We want our equation to look like this

y=mx+b

we know that m= -3 so we just need to find b

We can start by plugging in the ordered coordinates into our equation

3=(-3)(-2)+b

Solve for b

3=6+b

b= -3

Which means our final equation is

y= -3x-3

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In 1970, the average length of a major league baseball game was 150 minutes compared to 180 minutes in 2018. Calculate the absol

Pavlova-9 [17]

Answer:

30 min
20%

Step-by-step explanation:

The absolute change in game length is ...

(180 min) -(150 min) = 30 min . . . . change in game length

The relative change is expressed as a fraction of the original game length:

(30 min)/(150 min) × 100% = 20% . . . . relative change in game length

6 0

3 years ago

❤Please help sweeties!❤

Alona [7]

Answer:

satisfy both equations

Step-by-step explanation:

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2 years ago

A new car is purchased for 20700 dollars. The value of the car depreciates are 11% per year. What will the value of the car be,

ASHA 777 [7]

Answer: $5,744.61

Step-by-step explanation:

year 1 = -2,277

year 2 = -2026.53

year 3 = -1803.61

year 4 = -1605.21

year 5 = -1428.64

year 6 = -1271.49

year 7 = -1131.62

year 8 = -1007.17

year 9 = -896.36

year 10 = -797.76

year 11 = -710

you are subtracting 11% from each year.

5 0

2 years ago

How do you write 3.50 x 102 in standard form?

vekshin1

357 is your answer because all you do is solve the problem =

6 0

2 years ago

9. Determine how long it takes for 80% of the material to decay.

Vilka [71]

Using an exponential function, it is found that it takes 18.6 days for 80% of the material to decay.

The amount of a substance after t days is modeled by:

$A(t) = A(0)e^{-kt}$

In which:

k is the decay rate, as a decimal.

A(0) is the initial amount.

The half-life is of 8 days, hence $A(8) = 0.5A(0)$ , and this is used to find k.

$A(t) = A(0)e^{-kt}$

$0.5A(0) = A(0)e^{-8k}$

$e^{-8k} = 0.5$

$\ln{e^{-8k}} = \ln{0.5}$

$-8k = \ln{0.5}$

$k = -\frac{\ln{0.5}}{8}$

$k = 0.08664339757$

Hence:

$A(t) = A(0)e^{-0.08664339757t}$

The time it takes for 80% of the material to decay it t for which $A(t) = 0.2A(0)$ , hence:

$0.2A(0) = A(0)e^{-0.08664339757t}$

$e^{-0.08664339757t} = 0.2$

$\ln{e^{-0.08664339757t}} = \ln{0.2}$

$-0.08664339757t = \ln{0.2}$

$t = -\frac{\ln{0.2}}{0.08664339757}$

$t = 18.6$

It takes 18.6 days for 80% of the material to decay.

To learn more about exponential functions, you can take a look at brainly.com/question/24906920

5 0

2 years ago