Can I have some help with this? Construct a linear function that has a slope of -3 and passes through the point (-2,3).
1 answer:
Answer:
-3x-3
Step-by-step explanation:
We want our equation to look like this
y=mx+b
we know that m= -3 so we just need to find b
We can start by plugging in the ordered coordinates into our equation
3=(-3)(-2)+b
Solve for b
3=6+b
b= -3
Which means our final equation is
y= -3x-3
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