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2 years ago

HELP QUICK IM STRUGGLING!:(

Mathematics

2 answers:

snow_tiger [21]2 years ago

4 0

Answer: 6/11 or B

Step-by-step explanation: How you would get this answer is you would take the fraction and see if there is any number you can divide both the denominator + the numerator by if there is not a number that you can divide them both by then it is in simplest form. But, if there IS a number that you can divide them both by then no it is not in simplest form.

I hoped this helped! :)

lukranit [14]2 years ago

3 0

The answer is B hopefully this helped

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The graph of an equation with a negative discriminant always has which characteristic?

spin [16.1K]

Answer:

The graph does not intercept the x-axis

Step-by-step explanation:

Hi there!

When the discriminant is positive, it means that in the quadratic equation, you <em>can</em> take the square root of this number and end up with two distinct solutions, one negative and one positive. The graph will intercept the x-axis twice.

When the discriminant is zero, it means that you won't be taking the square root of any number in the quadratic equation and you'll end up with two solutions that are equal, or just one distinct solution. The graph will intercept the x-axis once.

When the discriminant is negative, it means that the quadratic has no real solutions, meaning that it does not intercept the x-axis. It is impossible to take the square root of a negative number.

I hope this helps!

7 0

2 years ago

En la tienda de mascotas "Animalo-T", se desea elevar un elefante de 2,900 kg utilizando una elevadora hidráulica de plato grand

Korvikt [17]

Answer:

Se requiere una fuerza de 854.473 newtons sobre el émbolo pequeño.

Step-by-step explanation:

Por el Principio de Pascal se conoce que el esfuerzo experimentado por el elefante es igual a la presión ejercida por el plato pequeño. Es decir:

$\frac{F_{1}}{A_{1}} = \frac{F_{2}}{A_{2}}$ (1)

Donde:

$F_{1}$ - Fuerza experimentada por el elefante, medida en newtons.

$F_{2}$ - Fuerza aplicada sobre el plato pequeño, medida en newtons.

$A_{1}$ - Área del plato grande, medida en metros cuadrados.

$A_{2}$ - Área del plato pequeño, medida en metros cuadrados.

La fuerza aplicada sobre el plato pequeño es:

$F_{2} = \left(\frac{A_{2}}{A_{1}} \right)\cdot F_{1}$

La fuerza experimentada por el elefante es su propio peso. Por otra parte, el área del plato es directamente proporcional al cuadrado de su diámetro. Es decir:

$F_{2} = \left(\frac{D_{2}}{D_{1}} \right)^{2}\cdot m\cdot g$ (2)

Donde:

$D_{1}$ - Diámetro del plato grande, medido en centímetros.

$D_{2}$ - Diámetro del plato pequeño, medido en centímetros.

$m$ - Masa del elefante, medida en kilogramos.

$g$ - Aceleración gravitacional, medida en metros por segundo cuadrado.

Si sabemos que $D_{1} = 0.75\,m$ , $D_{2} = 0.13\,m$ , $m = 2900\,kg$ y $g = 9.807\,\frac{m}{s^{2}}$ , entonces la fuerza a aplicar al émbolo pequeño es:

$F_{2} = \left(\frac{0.13\,m}{0.75\,m} \right)^{2}\cdot (2900\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)$

$F_{2} = 854.473\,N$

Se requiere una fuerza de 854.473 newtons sobre el émbolo pequeño.

3 0

2 years ago

Luisa recorded her dog’s weight, in kilograms, each week for 9 wk.

svp [43]

<span>In order to find the median weight we must arrange the given values in an ascending order and take the middle one. Doing so lets us see that the dog's median weight was 4.8 kg.</span>

3 0

2 years ago

In a random sample survey of 80 students at Torreys middle school, 24 students said that math was their favorite subject. There

ElenaW [278]

Answer:

Step-by-step explanation:

I say 90 because 24 is just a little higher than 1/4 of 80 and since 1/4 of 300 is 75, 90 is the best estimate based off the sample survey. Hope this helps!

8 0

1 year ago

F(5) if f(x) = 3x - 2

iragen [17]

Answer:

f(5)=12

Step-by-step explanation:

Replace all x by 5

f(5)=3(5)-2

multiply 3 and 5 together

f(5)=15-2

Simplify:

f(5)=13

Hope this helps!

7 0

2 years ago

Read 2 more answers