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Rom4ik [11]
3 years ago
5

Find the midpoint of the line segement from (5,-1) to (-2,-4)

Mathematics
1 answer:
kati45 [8]3 years ago
6 0

The formula of a midpoint between two points:

M\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)

We have (5, -1) and (-2, -4).

Substitute:

\dfrac{5+(-2)}{2}=\dfrac{3}{2}=1.5\\\\\dfrac{-1+(-4)}{2}=\dfrac{-5}{2}=-2.5

<h3>Answer: The midpoint is (1.5, -2.5).</h3>
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Simplify each expression by distributing and combined bf like terms (SHOW WORK) please
Dafna1 [17]

Answer:

c-39

1. rearrange terms

2.distribute

3.distribute

4. subtract the numbers

5. combine like terms

6.multiply by 1

8 0
3 years ago
!!!!!!!!!!!!!!!!!!!!! HELP !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
USPshnik [31]

Answer:

rectangular prism

Step-by-step explanation:

The sides fold up into a rectangular shaped box, or a prism. Hope this helps!

4 0
3 years ago
The point A has coordinates (-5,6) What point do we get when we reflect point A across the x-axis?
elena-s [515]

Answer:

(-5,-6)

Step-by-step explanation:

smart

3 0
3 years ago
Help plz:)))I’ll mark u Brainliest
noname [10]

Answer:

22-18-25,

19-24-30,

7-24-25

Step-by-step explanation:

In a triangle with side lengths a, b, and c, any two sides must have a sum larger than the third.

Using this rule, the possible side lengths out of these choices that could form a triangle are:

22-18-25,

19-24-30,

7-24-25

7 0
3 years ago
Where are the asymptotes of f(x) = tan(4x − π) from x = 0 to x = pi over 2 ?
vladimir1956 [14]
tan(4x- \pi )= \frac{sin(4x- \pi )}{cos(4x- \pi )}

The asymptotes are where the graph is undefined. Since: tan(x) =sin(x)/cos(x)
It is where cos(4x-π) = 0

cos(4x-π) = 0 when the inside is -π/2 , π/2 , 3π/2

4x - π = π/2
4x = π/2 + π
4x = 3π/2
x = 3π/8

4x - π = 3π/2
4x = 3π/2 + π
4x = 5π/2
x = 5π/8
This ones outside the interval (5π/8 > π/2) , try -π/2

4x - π = -π/2
4x = -π/2 + π
4x = π/2
x = π/8

Asymptotes are π/8 and 3π/8




4 0
3 years ago
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