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Aleksandr [31]
3 years ago
11

Evaluate 3x+4(y+3) when x is 5 less than the quotient of y and 3, and y=18.

Mathematics
1 answer:
romanna [79]3 years ago
4 0

It is given that x is 5 less than the quotient of y and 3.

And given value of y is 18 .

So quotient of y and 3 is

\frac{18}{3} = 6

And 5 less than 6 =1

So we have y=18 and x=1

Given expression is

3x+4(y+3)

At x=1 and y=18, we will get

3(1)+4(18+3) =3 + 4(21)

= 3+84=87

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