Question

Evaluate 3x+4(y+3) when x is 5 less than the quotient of y and 3, and y=18.

Answer 1

It is given that x is 5 less than the quotient of y and 3.

And given value of y is 18 .

So quotient of y and 3 is

$\frac{18}{3} = 6$

And 5 less than 6 =1

So we have y=18 and x=1

Given expression is

$3x+4(y+3)$

At x=1 and y=18, we will get

$3(1)+4(18+3) =3 + 4(21)$

$= 3+84=87$