Answer:
7/25
Step-by-step explanation:
Let 
so we have 
As 
, we'll have ![\cos[2\arcsin(\frac{3}{5})]=\bigr[\cos(\arcsin(\frac{3}{5}))\bigr]^2-\bigr[(\sin(\arcsin(\frac{3}{5}))\bigr]^2](https://tex.z-dn.net/?f=%5Ccos%5B2%5Carcsin%28%5Cfrac%7B3%7D%7B5%7D%29%5D%3D%5Cbigr%5B%5Ccos%28%5Carcsin%28%5Cfrac%7B3%7D%7B5%7D%29%29%5Cbigr%5D%5E2-%5Cbigr%5B%28%5Csin%28%5Carcsin%28%5Cfrac%7B3%7D%7B5%7D%29%29%5Cbigr%5D%5E2)
To determine 
, construct a right triangle with an opposite side of 3 and a hypotenuse of 5. This is because since 
, then 
. If you recognize the Pythagorean Triple 3-4-5, you can figure out that the adjacent side is 4, and thus, 
. This means that 
.
Hence, ![\cos[2\arcsin(\frac{3}{5})]=(\frac{4}{5})^2-(\frac{3}{5})^2=\frac{16}{25}-\frac{9}{25}=\frac{7}{25}](https://tex.z-dn.net/?f=%5Ccos%5B2%5Carcsin%28%5Cfrac%7B3%7D%7B5%7D%29%5D%3D%28%5Cfrac%7B4%7D%7B5%7D%29%5E2-%28%5Cfrac%7B3%7D%7B5%7D%29%5E2%3D%5Cfrac%7B16%7D%7B25%7D-%5Cfrac%7B9%7D%7B25%7D%3D%5Cfrac%7B7%7D%7B25%7D)
Answer:
1/3
Step-by-step explanation:
1) 1/6+1/6= 2/6
2) 2 and 6 can both be divide be 2.
2/2=1 and 6/2=3
Answer:
V = 4/3 π r 3
Step-by-step explanation:
Hope this helps!!
