Answer:
5:2
Step-by-step explanation:
10:4/2
5:2
Answer:
The options are not shown, so i will answer in a general way.
Let's define the variables:
h = number of hats
m = number of mugs.
We know that a total of 1000 items were ordered, then:
h + m = 1000
We also know that we have 3 times more mugs than hats, this can be written as:
m = 3*h
Now we have the system of equations:
h + m = 1000
m = 3*h
To solve these, we usually start by isolating one of the variables in one equation and then replace that in the other equation, but in this case, we already have m isolated in the second equation, then we can replace that in the first equation to get:
h + m = 1000
h + (3*h) = 1000
Now we can solve this equation for h, and find the number of hats ordered.
4*h = 1000
h = 1000/4 = 250
There were 250 hats ordered.
Answer:
47 bpm
B
Step-by-step explanation:
Draw a trend line (attached).
Reading from the graph, the resting hear rate, in bpm, of a person who exercises an average of 8 hours a week is approximately 47.
The only scatter plot that suggests a linear relationship between x and y is graph B (see second attachment) as the trend line is a straight line.
Answer:
S₁₆ = 328
Step-by-step explanation:
the nth term of an arithmetic sequence is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
given a₄ = 7 and a₇ = 16 , then
a₁ + 3d = 7 → (1)
a₁ + 6d = 16 → (2)
subtract (1) from (2) term by term to eliminate a₁
0 + 3d = 9
3d = 9 ( divide both sides by 3 )
d = 3
substitute d = 3 into (1) and solve for a₁
a₁ + 3(3) = 7
a₁ + 9 = 7 ( subtract 9 from both sides )
a₁ = - 2
the sum to n terms of an arithmetic sequence is
=
[ 2a₁ + (n - 1)d ]
with a₁ = - 2 and d = 3 , then
S₁₆ =
[ (2 × - 2) + (15 × 3) ]
= 8(- 4 + 45)
= 8 × 41
= 328
Answer:
No you do not.
This is because we can use Pythagoras Theorem to show that our location sits outside the 15 mile radius of the cell tower.
To work is out you would write the equation

Then to work out the Hypotheses you would

Which proves that the location is outside of the 15 Mile radius of the cell tower.