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aksik [14]
3 years ago
6

How do device drivers vary in complexity?​

Computers and Technology
1 answer:
BartSMP [9]3 years ago
3 0
I wanna know so bad i can’t wait till someone answers
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Based on a kc value of 0.150 and the data table given, what are the equilibrium concentrations of xy, x, and y, respectively?
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If the solution process is endothermic, then an increase in temperature usually results in an increase in solubility. Their heat of reaction is usually positive. The rest of the choices do not answer the question above.

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3 years ago
There are 3 parts to an osha inspection. What are they
vovikov84 [41]

1)<u> </u><u>An opening conference. The opening conference is a brief meeting during which the OSHA inspector will explain the purpose of the inspection.</u>


2) <u>A worksite “walkaround” The walkaround is the actual inspection.</u>


3) <u>A closing conference.</u>

6 0
3 years ago
When water reaches the pole, most of it turns to ice. Some salt is trapped between ice crystals, but most is left behind in the
astra-53 [7]

Answer:

b should be the right answer

Explanation:

8 0
3 years ago
Read 2 more answers
110101111.11011 to decimal (base 10)
Leokris [45]
The part 110101111 is 1+2+4+8+32+128+256 = <span>431

The part after the dot is 1/2 + 1/4 + 1/16 + 1/32 = </span>0.84375

Together that's 431.84375
4 0
4 years ago
java methods Write a program whose input is a character and a string, and whose output indicates the number of times the charact
AfilCa [17]

Answer:

Here is the JAVA program:

import java.util.Scanner; // for taking input from user

//class to count number of times a character appears in the string

public class CharacterCounter

//method which returns number of times a character appear in string

{ public static int CountCharacter(String userString, char character)

   {  

       int counter = 0;   //stores the no of times character appears in string

for (int i=0; i<userString.length(); i++) //loop moves through entire string

       { // if character matches the character in the string

           if (userString.charAt(i) == character)

           counter++;  // adds one to the character counter variable

       }  

       return counter;     } // returns no of time character is found in string

public static void main(String[] args) {

    Scanner scanner = new Scanner(System. in);//takes input from user

    String string;

    char character;

       System.out.println("Enter a string"); //prompts user to enter a string

       string = scanner.nextLine(); //scans the input string

       System.out.println("Enter a character");

       // prompts user to enter character

       character = scanner.next().charAt(0); //scans and reads the character

       System.out.println("number of times character "+character + " appears in the string " + string +": " + CountCharacter(string, character));  }  }

// calls CountCharacter method to output no of times a character appears in the input string

Explanation:

The method CountCharacter() has a loop in which the variable i works as an index which moves through each character of the string and if the character of the string in i matches the character which is to be found in the string then the value of counter variable increments by 1. This means that counter variable keeps counting the number of time the character appears in the string. The loop breaks when value of i exceeds the length of the string which means that the i reaches the end of the string and has searched the entire string for the specified character. In the end the count variable returns the number of time character appeared in the string. The main() function takes as input from the user, a string and a character to be searched for in the string. It then calls CountCharacter() function to find the number of times that input character appears in the input string and displays it on the output screen.

The program along with its output is attached as a screenshot.

5 0
4 years ago
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