Question

F(x)=2(x)^2+5 (x+2) f(2)

Answer 1

Answer:

f=

−2x^2+y /10x+20

Step-by-step explanation:

Let's solve for f.

y=2x^2+5(x+2)f(2)

Step 1: Flip the equation.

10fx+2x^2+20f=y

Step 2: Add -2x^2 to both sides.

10fx+2x^2+20f+−2x^2=y+−2x^2

10fx+20f=−2x^2+y

Step 3: Factor out variable f.

f(10x+20)=−2x^2+y

Step 4: Divide both sides by 10x+20.

f(10x+20) /

10x+20

=

−2x2+y

10x+20