Answer:
B= 52 pie m^3
Step-by-step explanation:
vol of a cylinder = pie*r^2× h
vol of a cone = 1/3 × pie*r^2×h
......vol of a cone with d same base nd height
= 1/3 × 156
= 156/3= 52m^3
Answer:
The answer is 17
Step-by-step explanation:

Answer:
sir can u please attach a photo of the 'relationship shown below'..?
Step-by-step explanation:
very sorry I need more context / question
The data below shows the average number of text messages sent daily by a group of people: 7, 8, 4, 7, 5, 2, 5, 4, 5, 7, 4, 8, 2,
enot [183]
It all depends. You've given us an incredibly vague question.
The outlier could be a number that's low or quite high. Also, outliers
shouldn't really contribute towards the value of the mean, median or
range related to a group of data.
They are called outliers because they are bizarre results or numbers
and should be detached from groups of data. Outliers by definition
are abnormalities or anomalies.
I'd say outliers don't really change anything, unless you actually want
to give them credibility or weight.
Large outliers can inflate the value of means, medians and ranges.
Small outliers will invariably deflate the value of means and medians.
Answer:
Probability both are nervous around strangers = 0.0049
Probability at least one is nervous around strangers = 0.1302
Step-by-step explanation:
Let probability a person selected in the population is nervous around strangers = P
P = 7%
P = 
P = 0.07
Let probability a person selected in the population is not nervous around strangers = P'
P' = 1 - P
P' = 1 - 0.07
P' = 0.93
(i) probability of the first person selected is nervous around strangers = P
probability of the second person selected is nervous around strangers = P
Probability both are nervous around strangers = (P × P)
= 0.07 × 0.07
= 0.0049
(ii) Probability at least one is nervous around strangers = ( probability the first person is nervous around strangers AND the second person is not nervous around strangers ) OR ( probability the second person is nervous around strangers AND the first person is not nervous around strangers)
This implies,
Probability at least one is nervous around strangers = (P × P') or (P × P')
= (0.07 × 0.93) + (0.07 × 0.93)
= 0.0651 + 0.0651
= 0.1302