Answer:
Step-by-step explanation:
If point I is on the line segment HJ, then HI+IJ = HJ
Given the parameters
H I = 2 x
H J = 4 x
IJ=4x−10
Substituting the given parameters into the formula;
2x+4x-10 = 4x
6x-10 = 4x
collect like terms
6x-4x = 10
2x = 10
divide both sides b 2;
2x/2 = 10/2
x = 5
Since IJ = 4x-10
Substitute x = 5 into IJ
IJ = 4(5)-10
IJ = 20-10
IJ = 10
its 10
x(6+7x)
The ans is -14 if you use desmos and start "finger counting" the slope of -3, y will equal -14 once it reaches (3,y)
We know that the Angle subtended by an arc on centre of the circle is double as that of Angle subtended by the same arc on the circumference (boundary) of the circle
So,
Multiplied by2x
2/x ×2x =1