14 hundreds, 10 tens, and 2 ones.
We can factor by grouping. To do so, we multiply the leading coefficient with the constant at the end. In other words, a times c (ax^2 + bx + c).
15*-4 = -60
Now we need to split the b term into two pieces that multiply to -60 and add to 4.
-6 and 10 will work.
Now group one part of b with the 15x^2 and the other part with -4.
(15x^2 + 10x) + (-6x - 4)
Now factor both terms.
5x(3x+2) - 2(3x+2)
3x+2 is one of our factors and 5x-2 is the other.
(3x+2)(5x-2)=0
Now just find the zeros.
3x+2 = 0
3x = -2
x = -2/3
And
5x-2 = 0
5x = 2
x = 2/5
So the answer is x = -2/3 and x = 2/5
Answer:
( -4, -3 )
Step-by-step explanation:
Let's solve by elimination. Reason being there are no variables without coefficients.
−5y+3x=3 Multiply equation by 3. Each term.
−8y+9x=−12
-15y + 9x = 9 Subtract the to equations
-8y + 9x = -12
___________
-7y = 21
y = -3
Substitute y into original equation
-5(-3) + 3x = 3
15 + 3x = 3 Subtract 15 both sides
3x = -12 Divide by 3, both sides
x = -4
Answer:
Erin gets £90
Step-by-step explanation:
Ratio = 5 : 2 : 7
Money with Erin = 5x
Money with Faye = 2x
Money with Sachin = 7x
Faye gets £90 less than Sachin
7x - 2x = 90
5x = 90
x = 90/5
x = 18
Money with Erin = 5*18 = 90
Answer:
4th option
Step-by-step explanation:
Given
A (- 5, 13 ) → A' (2, 9 )
- 5 → 2 → + 7 in the x- direction
13 → 9 → - 4 in the y- direction
The translation rule is
(x, y ) → (x + 7, y - 4 ) , then
B (4, - 2 ) → B' (4 + 7, - 2 - 4 ) → B' (11, - 6 )
